标签：app integer out nbsp i+1 pre more NPU spec
Given an integer array sorted in non-decreasing order, there is exactly one integer in the array that occurs more than 25% of the time.
Return that integer.
Example 1:
Input: arr = [1,2,2,6,6,6,6,7,10] Output: 6
Constraints:
1 <= arr.length <= 10^40 <= arr[i] <= 10^5class Solution { public int findSpecialInteger(int[] arr) { int cur = 0, max = 0, res = 0; if(arr.length == 1) return arr[0]; if(arr == null || arr.length == 0) return 0; for(int i = 0; i < arr.length - 1; i++){ if(arr[i] == arr[i+1]){ cur++; } else cur = 0; if(cur > max){ max = cur; res = arr[i]; } } System.out.println(max); return res; } }
HashMap也行，就是有点慢
1287. Element Appearing More Than 25% In Sorted Array
标签：app integer out nbsp i+1 pre more NPU spec
原文地址：https://www.cnblogs.com/wentiliangkaihua/p/12078967.html
