mysql——多表——子查询——示例

子查询：

子查询是将一个查询语句嵌套在另外一个查询语句中，内层查询语句的查询结果，可以作为外来层查询语句提供查询条件。

因此在特定条件下，一个查询语句的条件，需要另外一个查询语句来获取。

create table employee ( num int(50),
                        d_id int(50),
                        name varchar(50),
                        age int(50),
                        sex varchar(50),
                        homeadd varchar(50)
                       );



insert into employee values(1,1001,‘zhangsan‘,26,‘nan‘,‘beijing‘);
insert into employee values(2,1001,‘lisi‘,24,‘nv‘,‘hunan‘);
insert into employee values(3,1002,‘wangwu‘,25,‘nan‘,‘jiangsu‘);
insert into employee values(4,1004,‘aric‘,15,‘nan‘,‘yingguo‘);



select * from employee;







create table department ( d_id int(50),
                          d_name varchar(50),
                          functione varchar(50),
                          address varchar(50)
                        );



insert into department values(1001,‘keyanbu‘,‘yanfachanpin‘,‘3lou5hao‘);
insert into department values(1002,‘shengchanbu‘,‘shengchanchanp‘,‘5louyiceng‘);
insert into department values(1003,‘xiaoshoubu‘,‘cehuaxiaoshou‘,‘1louxiaoshoudating‘);




select * from department;

select * from employee where d_id in (select d_id from department );

select * from employee where d_id not in (select d_id from department );

select * from employee where exists (select d_name from department where d_id = 1003);

select * from employee where exists (select d_name from department where d_id = 1004);

exists关键字可以与其他查询条件一起使用。条件表达式与exists关键字之间用and或者or来连接。

select * from employee where age > 24 and exists (select d_name from department where d_id = 1003);

select * from employee where age > 24 and exists (select d_name from department where d_id = 1004);


not exists与exists相反。

select * from employee where age > 24 and not exists (select d_name from department where d_id = 1003);

select * from employee where age > 24 and not exists (select d_name from department where d_id = 1004);

create table schoarship ( levela int(50),
                          score int(50)
                         );


insert into schoarship(levela,score) values(1,90);
insert into schoarship values(2,80);
insert into schoarship values(3,70);


select * from schoarship;




create table computer_stu (  id int(50),
                             name varchar(50),
                             score int(50)
                           );


insert into computer_stu(id,name,score) values (1001,‘lily‘,85);

insert into computer_stu(id,name,score) values (1002,‘tom‘,91),
                                               (1003,‘jim‘,87),
                                               (1004,‘aric‘,77),
                                               (1005,‘lucy‘,65),
                                               (1006,‘andy‘,99),
                                               (1007,‘ada‘,85),
                                               (1008,‘jeck‘,70);


select * from computer_stu;

select id,name,score from computer_stu where score >= (select score from schoarship where levela = 1);

/* 查询获得一等奖学金的学生有哪些，第一个表为奖学金等级和最低分数*/

select d_id,d_name from department where d_id != (select d_id from employee where age = 24);

/*只有生产部和销售部没有年龄等于24岁的员工*/

select * from computer_stu where score >= any ( select score from schoarship );

/*结果显示，有7个人获得奖学金，只有id为1005的人没有，因为分数为65，不高于奖学金指定最低分数的任何一个*/

select * from computer_stu where score >= all ( select score from schoarship );

/*结果显示，只有两个人获得奖学金。因为这两个人的分数比所有奖学金要求的分数都高*/