数组本质分析

 1 #include <stdio.h>
 2 int main()
 3 {
 4      int a[5] = {1,2};
 5      int b[] = { 3, 4 };
 6      printf("a[2]=%d\n",a[2]);
 7      printf("a[3]=%d\n",a[3]);
 8      printf("sizeof(a)=%d\n",sizeof(a));
 9      printf("sizeof(b)=%d\n", sizeof(b));
10      printf("数组a的元素个数=%d\n",sizeof(a)/sizeof(a[0]));
11      printf("数组b的元素个数=%d\n", sizeof(b) / sizeof(b[0]));
12      printf("&a=%p\n",&a);
13      printf("&a[0]=%p\n", &a[0]);
14      printf("a=%p\n",a);
15      return 0;
16 }
17 运行结果：
18 a[2]=0
19 a[3]=0
20 sizeof(a)=20
21 sizeof(b)=8
22 数组a的元素个数=5
23 数组b的元素个数=2
24 &a=004FF9F4
25 &a[0]=004FF9F4
26 a=004FF9F4
27 请按任意键继续. . .

 1 #include <stdio.h>
 2 int main()
 3 {
 4      int a[5] = { 0 };
 5      int b[2];
 6      int *p = NULL;
 7      p = a;
 8      printf("a=%p\n",a);
 9      printf("p=%p\n",p);
10      printf("&p=%p\n",&p);
11      printf("sizeof(a)=%d\n",sizeof(a));
12      printf("sizeof(p)=%d\n", sizeof(p));
13      return 0;
14 }
15 运行结果：
16 a=004FFBD4
17 p=004FFBD4
18 &p=004FFBB8
19 sizeof(a)=20
20 sizeof(p)=4
21 请按任意键继续. . .