MySQL随记 - 连接查询

标签：last   like   com   employees   实现   select   group by   一个   jobs   

一、连接分类

1. 内连接
    (1)等值连接
    (2)非等值连接
    (3)自连接
2. 外连接
    (1)左外连接
    (2)右外连接
    (3)全外连接
3. 交叉连接

二、外连接

# 等值连接
# 案例1：查询员工名对应的部门名
SELECT last_name, department_name
FROM employees, departments
WHERE employees.`department_id` = departments.`department_id`;

# 案例2：查询有奖金的员工名、部门名
SELECT last_name, department_name, commission_pct
FROM employees AS e, departments AS d
WHERE e.`department_id` = d.`department_id`
AND commission_pct IS NOT NULL;

# 案例3：查询城市名中第二个字符为o的部门名和城市名
SELECT department_name, city
FROM departments AS d, locations AS l
WHERE d.`location_id` = l.`location_id`
AND city LIKE '_o%';

# 案例4：查询每个城市的部门个数
SELECT COUNT(*), city, department_name
FROM departments AS d, locations AS l
WHERE d.`location_id` = l.`location_id`
GROUP BY city;

# 案例5：查询有奖金的每个部门名和部门的领导编号和该部门的最低工资
SELECT department_name, d.manager_id,MIN(salary)
FROM departments AS d, employees AS e
WHERE d.`department_id` = e.`department_id`
AND commission_pct IS NOT NULL
GROUP BY department_name, d.manager_id;

# 案例6；查询每个工种的工种名和员工的个数，并且按员工个数降序
SELECT job_title, COUNT(*)
FROM employees AS e, jobs AS j
WHERE e.`job_id` = j.`job_id`
GROUP BY job_title
ORDER BY COUNT(*) DESC;

# 案例7：查询员工名、部门名和所在城市
SELECT last_name, department_name, city
FROM departments AS d, employees AS e, locations AS l
WHERE d.`department_id` = e.`department_id` AND d.`location_id` = l.`location_id`;

三、外连接

应用场景：用于查询一个表中有，另一个表没有的记录
特点：
1.外连接的查询结果为主表中的所有记录
    如果从表中有和它匹配的，则显示匹配的值
    如果从表中没有和它匹配的，则显示null
    外连接查询结果=内连接结果+主表中有而从表没有的记录
2.左外连接，left join左边的是主表；右外连接，right join右边的是主表
3.左外和右外交换两个表的顺序，可以实现同样的结果
4.全外连接=内连接的结果+表1中有但表2没有的+表2中有表1没有的·

MySQL随记 - 连接查询

标签：last   like   com   employees   实现   select   group by   一个   jobs   

原文地址：https://www.cnblogs.com/hq82/p/12243093.html