标签:strcmp 需要 描述 结束 技术 hud 输入 rcm ***
1.编写一个要求用户输入两个整数的程序,将程序将计算并输出这两个整数之间(包括这两个整数)所有的整数的和。这里假设先输入较小的整数,例如如果用户输入的是2和9,则程序将指出2-9之间所有整数的和为44.
1 #include<iostream>
2 using namespace std;
3
4 int main()
5 {
6 int a, b;
7 int cnt = 0;
8 cin >> a >> b;
9 for (int i = a; i <= b; i++)
10 {
11 cnt = cnt + i;
12 }
13 cout << cnt;
14 while (1);
15 return 0;
16 }
2.使用array对象(而不是数组)和long double(而非long long)重新编写程序清单5.4,并计算100!的值。
1 #include<iostream>
2 #include<array>
3 using namespace std;
4
5 const int ArSize = 101;
6
7 int main()
8 {
9 array <long double, ArSize> cnt;
10 cnt[1] = cnt[0] = 1L; //long double型用L做后缀
11 for (int i = 2; i < ArSize; i++)
12 {
13 cnt[i] = i*cnt[i - 1];
14 }
15 for (int i = 0; i < ArSize; i++)
16 {
17 cout << i << "! = " << cnt[i] << endl;
18 }
19 while (1);
20 return 0;
21 }
3.编写一个要求用户输入数字的程序。每次输入后,程序都将报告到目前为止,所有输入的累积和,输入0时,程序结束
1 #include<iostream>
2 using namespace std;
3
4 int main()
5 {
6 int n, cnt = 0;
7 cin >> n;
8 while (n!=0)
9 {
10 cnt += n;
11 cout << "截至目前为止,输入累计和为:" << cnt << endl;
12 cin >> n;
13 }
14 if (n == 0)
15 {
16 cout << "程序结束";
17 }
18 while (1);
19 return 0;
20 }
4、 Daphne以10%的单利投资了100美元。也就是说,每一年的利润都是投资额的10%(利息=0.10*原始存款)。而Cleo以5%的复利投资了100美元。也就是说,利息是当前存款(包括获得的利息)的5%(利息=0.05*当前存款)。请计算多少年后,Cleo的投资价值才能超过Daphne的投资价值,并显示此时两人的投资价值。
1 #include<iostream>
2 using namespace std;
3
4 int main()
5 {
6 double dap = 100, celo = 100;
7 int year=0;
8 while (celo<=dap)
9 {
10 dap += (100 * 0.10);
11 celo += celo*0.05;
12 year++;
13 }
14 cout << "After " << year << " years, Celo pass Daphne." << endl;
15 cout << "Daphne: " << dap << endl;
16 cout << "Celo: " << celo << endl;
17 system("pause");
18 return 0;
19 }
5、 假设要销售《C++ For Fools》一书,请编写一个程序,输入全年中每个月的销售量(图书数量,而不是销售额)。程序通过循环,使用初始化为月份字符串的char * 数组(或string对象数组)逐月进行提示,并将输入的数据存储在一个int数组中。然后,程序计算数组中各元素的总和,并报告这一年的销售情况。
1 #include<iostream>
2 #include<string>
3 using namespace std;
4 int main()
5 {
6 int sales[12], cnt = 0;
7 string month[12] = { "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December" }; //可替换为char *month[12]
8 for (int i = 0; i < 12; i++)
9 {
10 cout << month[i] << ": ";
11 cin >> sales[i];
12 }
13 for (int i = 0; i < 12; i++)
14 {
15 cnt += sales[i];
16 }
17 cout << "The total sales of this year is " << cnt << endl;
18 system("pause");
19 return 0;
20 }
6、 完成编程练习5,但这一次使用一个二维数组来存储输入——3年中每个月的销售量,程序将报告每年销售量以及三年的总销售量。
1 #include<iostream>
2 #include<string>
3 using namespace std;
4 int main()
5 {
6 int sales[3][12], cnt[3] = {}, total = 0;
7 string month[12] = { "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December" };
8 for (int i = 0; i < 3; i++)
9 {
10 cout << "Enter number " << i + 1 << " year‘s sales. " << endl;
11 for (int j = 0; j < 12; j++)
12 {
13 cout << month[j] << ": ";
14 cin >> sales[i][j];
15 cnt[i] += sales[i][j];
16 }
17 cout << endl;
18 }
19 for (int i = 0; i < 3; i++)
20 {
21 cout << "The total sales of number " << i + 1 << " year is " << cnt[i] <<" ."<< endl;
22 total += cnt[i];
23 }
24 cout << "The total sales of three years is " << total <<" ."<< endl;
25 system("pause");
26 return 0;
27 }
7、设计一个名为car的结构,用它存储下述有关汽车的信息:生产商(存储在字符数组或string对象中的字符串)、生产年份(整数)。编写一个程序,向用户询问有多少辆汽车。随后,程序使用new来创建一个由相应数量的car结构组成的动态数组。接下来,程序提示用户输入每辆车的生产商(可能有多个单词组成)和年份信息。请注意,这需要特别小心,因为它将交替读取数值和字符串。最后,程序将显示每个结构的内容。该程序的运行情况如下:
How many cars do you wish to catalog? 2
Car #1:
Please enter the make: Hudson Hornet
Please enter the year made: 1952
Car #2:
Please enter the make: Kaiser
Please enter the year made: 1951
Here is your collection:
1952 Hudson Hornet
1951 Kaiser
1 #include<iostream>
2 #include<string>
3 using namespace std;
4
5 struct car
6 {
7 string name;
8 int year;
9 };
10
11 int main()
12 {
13 int n;
14 cout << "How many cars do you wish to catalog ? ";
15 cin >> n;
16 car *pr = new car[n];
17 for (int i = 0; i < n; i++)
18 {
19 cout << "Car #" << i+1 << ":" << endl;
20 cout << "Please enter the make: ";
21 cin.get(); //前面cin>>n导致输入队列中留下了换行符,cin.getline()看到换行符后,将认为是一个空行,并将一个空字符串赋给pr[i].name
22 //此处cin.get()用来跳过前面cin>>n和每次循环cin>>pr[i].year留下的换行符
23 getline(cin, pr[i].name);
24 cout << "Please enter the year made: ";
25 cin >> pr[i].year;
26 }
27 cout << "Here is your collection: " << endl;
28 for (int i = 0; i < n; i++)
29 {
30 cout << pr[i].year << " " << pr[i].name << endl;
31 }
32 delete[]pr; //记得进行delete
33 system("pause");
34 return 0;
35 }
8、编写一个程序,它使用一个char数组和循环来每次读取一个单词,直到用户输入done为止。随后,该程序指出用户输入了多少单词(不包括done在内)。下面是该程序的运行情况:
Enter words (to stop, type the word done):
anteater birthday category dumpster
envy finagle geometry done for sure
You enter a total of 7words.
你应在程序中包含头文件cstring,并使用strcmp( )来进行比较测试。
1 #include<iostream>
2 #include<string>
3 using namespace std;
4
5 int main()
6 {
7 char word[20];
8 int number = 0;
9 cout << "Enter words (to stop, type the word done):" << endl;
10 do
11 {
12 cin >> word;
13 number++;
14 } while (strcmp(word,"done")!=0);
15 cout << "You entered a total of " << number-1 << " words.";
16 //方法二
17 /*
18 cin >> word;
19 while (strcmp(word, "done") != 0)
20 {
21 if (bool(cin >> word) == true)
22 {
23 number++;
24 }
25 }
26 cout << "You entered a total of " << number << " words.";
27 */
28 system("pause");
29 return 0;
30 }
9、编写一个满足前一个练习中描述的程序,但使用string对象而不是字符数组。请在程序中包含头文件string,并使用关系运算符来进行比较测试。
1 #include<iostream>
2 #include<string>
3 using namespace std;
4
5 int main()
6 {
7 string word;
8 int number = 0;
9 cout << "Enter words (to stop, type the word done):" << endl;
10 do
11 {
12 cin >> word;
13 number++;
14 } while (word!="done");
15 cout << "You entered a total of " << number-1 << " words.";
16 //方法二
17 /*
18 cin >> word;
19 while (word!="done")
20 {
21 if (bool(cin >> word) == true)
22 {
23 number++;
24 }
25 }
26 cout << "You entered a total of " << number << " words.";
27 */
28 system("pause");
29 return 0;
30 }
10、编写一个使用循环嵌套的程序,要求用户输入一个值,指出要显示多少行。然后,程序将显示相应行数的星号,其中第一行包含一个星号,第二行包含两个星号,依次类推。每一行包含的字符数等于用户指定的行数,在星号不够的情况下,在星号前面加上句点。该程序的运行情况如下:
Enter number of rows: 5
....*
...**
..***
.****
*****
1 #include<iostream>
2 using namespace std;
3
4 int main()
5 {
6 int n;
7 cout << "Enter number of rows: ";
8 cin >> n;
9 for (int i = 1; i <= n; i++)
10 {
11 for (int j = n - i; j >0; j--)
12 {
13 cout << ‘.‘;
14 }
15 for (int k = 1; k <= i; k++)
16 {
17 cout << ‘*‘;
18 }
19 cout << endl;
20 }
21 system("pause");
22 return 0;
23 }
[C++ Primer Plus] 第5章、循环和关系表达式——(二)课后习题
标签:strcmp 需要 描述 结束 技术 hud 输入 rcm ***
原文地址:https://www.cnblogs.com/Fionaaa/p/12283463.html