标签:this set 起点 java false end sort code const
1 //A算法 自动寻路 路径 2 class GetAutoPath{ 3 4 constructor(id, map, sPos, ePos, mapArr){ 5 //this.type = id.type; 6 this.id = id; 7 this.map = map; 8 this.sPos = sPos; 9 this.ePos = ePos; 10 this.mapArr = mapArr; 11 this.maxMach = 10000; 12 this.openArr = []; 13 this.closeArr = []; 14 this.minPath = []; 15 if(!this.isPath(this.sPos.x, this.sPos.y)){this.sPos = this.getNewDot(sPos, ePos);} 16 if(!this.isPath(this.ePos.x, this.ePos.y)){this.ePos = this.getNewDot(ePos, sPos);} 17 //console.log(this.mapArr); 18 return this.run(); 19 } 20 21 posts(txt, arr){//post消息 22 //let id = this.id, sPos = this.sPos, ePos = this.ePos, arrs = arr || []; 23 return {id:this.id, map:this.map, arr:arr || [], sPos:this.sPos, ePos:this.ePos, txt:txt} 24 } 25 26 isPath(x, y){//isPath = true 合法路径 = isBanPath === undefined 27 let isPath = false, ym = this.mapArr.get(y), xm; //console.log(ym); debugger; 28 if(ym !== undefined){ 29 xm = ym.get(x); 30 if(xm !== undefined){ 31 if(xm.isBanPath === undefined){isPath = true;} 32 } 33 } 34 //if(this.mapArr[y] !== undefined && this.mapArr[y][x] !== undefined && this.mapArr[y][x].isPath === 1){isPath = true;} 35 return isPath; 36 } 37 38 getEqual(arr, x, y){//获取目标数组相同的坐标 39 let isPos = false; 40 if(arr.length === 0){ 41 isPos = false; 42 }else{ 43 isPos = arr.some(function (o){return o.x === x && o.y === y;}); 44 } 45 return isPos; 46 } 47 48 getDot(x, y){//获取周围8个方向坐标 49 return [{x:x-1,y:y},{x:x+1,y:y},{x:x,y:y-1},{x:x,y:y+1},{x:x-1,y:y-1},{x:x+1,y:y+1},{x:x+1,y:y-1},{x:x-1,y:y+1}] 50 } 51 52 getNewDot(setPos, pos){//重定义起点或终点 53 let dot = setPos, pointDot, k, arr = [], arrs = [], g, end, maxMachT = 0; 54 while(!end && maxMachT < this.maxMach){ 55 maxMachT++; 56 pointDot = this.getDot(dot.x, dot.y); 57 for(k in pointDot){ 58 g = Math.round(Math.sqrt(Math.abs(pointDot[k].x - pos.x) + Math.abs(pointDot[k].y - pos.y)) * 100) / 100; 59 if(!this.isPath(pointDot[k].x, pointDot[k].y)){//不合法 60 arr.push({x:pointDot[k].x, y:pointDot[k].y, g:g}); 61 arr.sort(function(a, b){return a.g - b.g;}); 62 }else{//合法 63 arrs.push({x:pointDot[k].x, y:pointDot[k].y, g:g}); 64 arrs.sort(function(a, b){return a.g - b.g;}); 65 } 66 if(arrs.length > 0){end = true;} 67 } 68 dot = {x:arr[0].x, y:arr[0].y, g:arr[0].g}; arr = []; 69 } 70 if(!arrs[0].x || !arrs[0].y){return this.posts("没有符合的坐标");} 71 return {x:arrs[0].x, y:arrs[0].y}; 72 } 73 74 run(){ 75 if(this.sPos.x === undefined || this.ePos.x === undefined){return this.posts("没有符合的坐标");} 76 let sPos = this.sPos, ePos = this.ePos, point, key, i, newPoint, ger, gers, g, h, f, maxMachT = 0; 77 this.openArr[0] = {x : sPos.x, y : sPos.y, f : 0, p : 0, ger : 0} 78 while(this.openArr.length > 0){ 79 maxMachT++; 80 point = this.openArr[0]; this.closeArr.push(point); this.openArr.splice(0,1); 81 key = this.closeArr.length - 1;//设置当前节点 82 newPoint = this.getDot(point.x, point.y);//获取周围点 83 for(i in newPoint){//设置周围点 84 ger = Math.round(Math.sqrt(Math.abs(newPoint[i].x - point.x) + Math.abs(newPoint[i].y - point.y)) * 100) / 100;//到当前节点的曼哈顿距离,保留两位小数点 85 gers = ger + point.ger; 86 g = Math.round(gers * 100) / 100; 87 h = Math.abs(newPoint[i].x - ePos.x) + Math.abs(newPoint[i].y - ePos.y); 88 f = g + h; 89 if(this.isPath(newPoint[i].x, newPoint[i].y) && !this.getEqual(this.openArr, newPoint[i].x, newPoint[i].y) && !this.getEqual(this.closeArr, newPoint[i].x, newPoint[i].y)){this.openArr.push({x:newPoint[i].x, y:newPoint[i].y, f:f, p:key, ger:ger});} 90 } 91 this.openArr.sort(function(a, b){return a.f - b.f;});//排序 92 if(this.getEqual(this.closeArr, ePos.x, ePos.y) || this.getEqual(this.openArr, ePos.x, ePos.y)){//end 93 this.minPath.unshift(this.closeArr[key]); 94 while(this.minPath.length > 0){ 95 if(this.minPath[0].p == 0){return this.posts(‘success‘, this.minPath);}else{this.minPath.unshift(this.closeArr[this.minPath[0].p]);} 96 } 97 }else if(maxMachT === this.maxMach){ 98 return this.posts("没有符合的坐标"); 99 } 100 } 101 return this.posts("没有符合的坐标"); 102 } 103 104 }
标签:this set 起点 java false end sort code const
原文地址:https://www.cnblogs.com/weihexinCode/p/12318344.html