标签:ret with The sorted desc excel one current nbsp
notes:
1 """ 2 created by sheepcore on 2020-03-02 3 """ 4 from typing import List 5 6 7 def smallerNumbersThanCurrentV2(nums: List[int]) -> List[int]: 8 """ 9 excellent solution by mudin 10 :param nums: 11 :return: 12 """ 13 return [sorted(nums).index(a) for a in nums] 14 15 16 def smallerNumbersThanCurrent(nums: list()) -> list(): 17 """ 18 This is my solution. 19 :param nums: 20 :return: 21 """ 22 i = 0 23 res = list() 24 while i < len(nums): 25 cur = nums[i] 26 smaller = 0 27 j = 0 28 while j < len(nums): 29 if j != i and nums[j] < nums[i]: 30 smaller += 1 31 j += 1 32 res.append(smaller) 33 i += 1 34 return res
LeetCode-1365 How Many Numbers Are Smaller Than the Current Number Solution with python
标签:ret with The sorted desc excel one current nbsp
原文地址:https://www.cnblogs.com/sheepcore/p/12394070.html