【计算机二级C语言】卷008

标签：异或   fprintf   c中   大写   开发   函数返回值   树形结构   文字   ide   

选择题

公共知识

【10】有三个关系R、S和T如下:
则由关系R和S得到关系T的操作是()。

专业知识

if (a < b)
if (a < c) k = a;
else k = c;
else
if (b < c) k = b;
else k = c;

#include <stdio.h>
void main()
{
    int k = 5;
    while (--k) printf("%d", k- = 3);
    printf("\n");
}

#include <stdio.h>
void main()
{
    int i, j;
    for (i = 3; i >= 1; i--)
    {
        for (j = 1; j <= 2; j++) printf("%d ", i + j);
        printf("\n");
    }
}

#include <stdio.h>
void main()
{
    int k = 5, n = 0;
    do
    {
        switch (k)
        {
            case 1: case 3: n+ = 1; k--; break;
            default: n = 0; k--;
            case 2: case 4: n+ = 2; k--; break;
        }
        printf("%d", n);
    }
    while (k > 0 && n < 5);
}

int fun(int *p)
{ return * p; }
fun函数返回值是

double a[10], *s = a;

#include <stdio.h>
void f(int *q)
{
    int i = 0;
    for (; i < 5; i++)(*q)++;
}
void main()
{
    int a[5] = { 1, 2, 3, 4, 5 }, i;
    f(a);
    for (i = 0; i < 5; i++) printf("%d,", a[i]);
}

#include <stdio.h>
int fun(int(*s)[4], int n, int k)
{
    int m, i;
    m = s[0][k];
    for (i = 1; i < n; i++)
    if (s[i][k] > m)
    m = s[i][k];
    return m;
}
void main()
{
    int a[4][4] = {
        {1, 2, 3, 4 },
        { 11, 12, 13, 14 },
        { 21, 22, 23, 24 },
    { 31, 32, 33, 34 } };
    printf("%d\n", fun(a, 4, 0));
}

char *s1 ="OK", *s2 ="ok";

#include <stdio.h>
void fun(char **p)
{
    ++p;
    printf("%s\n", *p);
}
void main()
{
    char *a[] = {"Morning","Afternoon","Evening","Night"};
    fun(a);
}

#include <stdio.h>
#include <ctype.h>
void fun(char *p) {
    int i = 0;
    while (p[i])
    {
        if (p[i] == ' ' && islower(p[i - 1]))
        p[i - 1] = p[i - 1] - 'a' + 'A';
        i++;
    }
}
void main()
{
    char s1[100] ="ab cd EFG !";
    fun(s1);
    printf("%s\n", s1);
}

#include <stdio.h>
int f(int x)
{
    int y;
    if (x == 0 || x == 1) return (3);
    y = x * x - f(x - 2);
    return y;
}
void main()
{
    int z;
    z = f(3);
    printf("%d\n", z);
}

#include <stdio.h>
int fun(int x[], int n)
{
    static int sum = 0, i;
    for (i = 0; i < n; i++) sum+ = x[i];
    return sum;
}
void main()
{
    int a[] = { 1, 2, 3, 4, 5 }, b[] = { 6, 7, 8, 9 }, s = 0;
    s = fun(a, 5) + fun(b, 4);
    printf("%d\n", s);
}

struct STD
{
    char name[10];
    int age;
    char sex;
} s[5], *ps;
ps = &s[0];

typedef struct S
{ int g; char h; } T;

#include <stdio.h>
#include <string.h>
struct A
{
    int a;
    char b[10];
    double c;
};
struct A f(struct A t);
void main()
{
    struct A a = { 1001,"ZhangDa", 1098.0 };
    a = f(a);
    printf("%d,%s,%6.1f\n", a.a, a.b, a.c);
}
struct A f(struct A t)
{
    t.a = 1002;
    strcpy(t.b,"ChangRong");
    t.c = 1202.0;
    return t;
}

#define IsDIV(k, n)((k % n == 1) ? 1: 0)

#include <stdio.h>
void main()
{
    int a = 1, b = 2, c = 3, x;
    x = (a^b) & c;
    printf("%d\n", x);
}

#include <stdio.h>
void main()
{
    FILE * fp;
    int k, n, a[6] = { 1, 2, 3, 4, 5, 6 };
    fp = fopen("d2.dat","w");
    fprintf(fp,"%d%d%d\n", a[0], a[1], a[2]);
    fprintf(fp,"%d%d%d\n", a[3], a[4], a[5]);
    fclose(fp);
    fp = fopen("d2.dat","r");
    fscanf(fp,"%d%d", &k, &n);
    printf("%d %d\n", k, n);
    fclose(fp);
}

编程题

【43】使用VC++2010打开考生文件夹下prog1中的解决方案。此解决方案的项目中包含一个源程序文件prog1.c。在此程序中, 编写函数fun, 该函数的功能是: 求出二维数组周边元素之和, 作为函数值返回。二维数组中的值在主函数中赋予。
例如, 若二维数组中的值为:

则函数值为61。
注意: 部分源程序在文件prog1.c中。
请勿改主动函数main和其他函数中的任何内容, 仅在函数fun的花括号中填入你编写的若干语句。

【计算机二级C语言】卷008

标签：异或   fprintf   c中   大写   开发   函数返回值   树形结构   文字   ide   

原文地址：https://www.cnblogs.com/mjios/p/12452735.html