标签:getch ons for tree pac test col ace ring
这个点的水可以从其他点来,也可以从0号结点来,所以把0号结点当成超级源点,然后跑最小生成树
#include <iostream> #include <cstdio> #include <queue> #include <algorithm> #include <cmath> #include <cstring> #define inf 2147483647 #define N 1000010 #define p(a) putchar(a) #define For(i,a,b) for(long long i=a;i<=b;++i) using namespace std; long long n,cnt,x,ans,y; long long d[N]; struct tree{ long long l; long long r; long long v; bool operator < (const tree &x) const{ return v<x.v; } }e[N]; void in(long long &x){ long long y=1;char c=getchar();x=0; while(c<‘0‘||c>‘9‘){if(c==‘-‘)y=-1;c=getchar();} while(c<=‘9‘&&c>=‘0‘){ x=(x<<1)+(x<<3)+c-‘0‘;c=getchar();} x*=y; } void o(long long x){ if(x<0){p(‘-‘);x=-x;} if(x>9)o(x/10); p(x%10+‘0‘); } long long find(long long x){ if(d[x]==x) return x; return d[x]=find(d[x]); } signed main(){ in(n); For(i,1,n) d[i]=i; For(i,1,n){ in(x); e[++cnt].l=0; e[cnt].r=i; e[cnt].v=x; } For(i,1,n) For(j,1,n){ in(x); if(i<j){ e[++cnt].l=i; e[cnt].r=j; e[cnt].v=x; } } sort(e+1,e+cnt+1); For(i,1,cnt){ x=find(e[i].l); y=find(e[i].r); if(x!=y){ ans+=e[i].v; d[x]=y; } } o(ans); return 0; }
https://vjudge.net/contest/363991#problem/C
标签:getch ons for tree pac test col ace ring
原文地址:https://www.cnblogs.com/war1111/p/12584970.html