标签:find 需要 长度 lan 否则 数组 error sel 更新
class Node(object):
def __init__(self, value=None, next=None):
self.value, self.next = value, next
class LinkedList(object):
def __init__(self, msxsize=None):
# msxsize=None代表无限大
self.maxsize = msxsize
# self.root 是根节点,根节点的next一般指向头节点head节点
self.root = Node()
self.length = 0
# self.tailnode表示最后一个节点
self.tailnode = None
def __len__(self):
return self.length
def append(self, value):
# 判断当前最大值是否超过了允许的最大值
if self.maxsize is not None and len(self) > self.maxsize:
raise Exception("Full")
node = Node(value)
tailnode = self.tailnode
if tailnode is None:
# 表明现在只有一个root节点, 然后指向当前的node节点即可
self.root.next = node
else:
# 否则把最后一个节点的next指向当前的node节点
self.tailnode.next = node
# 更新最后一个节点为node,因为我们把node放到了最后,而self.tailnode代表最后一个节点,所以要更新
self.tailnode = node
# 链表长度加一
self.length += 1
def appendleft(self, value):
# 定义头节点
headnode = self.root.next
node = Node(value)
# 根节点指向新的head节点: node节点
self.root.next = node
# node节点指向之前的head节点
node.next = headnode
self.length += 1
def iter_node(self):
# 第一个节点
curnode = self.root.next
# 当前节点不是最后一个节点时
while curnode is not self.tailnode:
yield curnode
# 当前节点更新为下一个节点
curnode = curnode.next
# 寻找到最后节点时,也需要把最后一个节点yield出来
yield curnode
def __iter__(self):
for node in self.iter_node():
yield node.value
def remove(self, value):
"""
删除包含值的一个节点,将其前一个节点的next指向下一个节点即可 O(n)
:param value:
:return:
"""
# 根节点
prevnode = self.root
for curnode in self.iter_node():
if curnode.value == value:
prevnode.next = curnode.next
if curnode is self.tailnode:
# 注意更新 tailnode
self.tailnode = prevnode
del curnode
self.length -= 1
# 返回1代表成功
return 1
else:
# 更新 prevnode
prevnode = curnode
# 返回-1表示删除失败
return -1
def find(self, value):
# O(n)
index = 0
for node in self.iter_node():
if node.value == value:
return index
index += 1
# 返回-1表示没找到
return -1
def popleft(self):
# O(1)
if self.root.next is None:
raise Exception("pop from empty LinkedList")
headnode = self.root.next
# 根节点指向头节点的下一个节点
self.root.next = headnode.next
value = headnode.value
self.length -= 1
del headnode
return value
def clear(self):
for node in self.iter_node():
del node
self.root.next = None
self.length = 0
class FullError(Exception):
pass
class EmptyError(Exception):
pass
class Queue(object):
def __init__(self, maxsize):
self.maxsize = maxsize
self._item_linked_list = LinkedList()
def __len__(self):
return len(self._item_linked_list)
def push(self, value):
if self.maxsize is not Node and len(self) >= self.maxsize:
raise FullError("queue full")
return self._item_linked_list.append(value)
def pop(self):
if len(self) == 0:
raise EmptyError("queue empty")
return self._item_linked_list.popleft()
class Node(object):
def __init__(self, value=None, prev=None, next=None):
self.value, self.prev, self.next = value, prev, next
class CirculaDoubleLinkedList(object):
def __init__(self, msxsize=None):
# msxsize=None代表无限大
self.maxsize = msxsize
node = Node()
node.next, node.prev = node, node
self.root = node
self.length = 0
def __len__(self):
return self.length
def headnode(self):
return self.root.next
def tailnode(self):
# 根节点的prev指向尾节点
return self.root.prev
def append(self, value):
# 判断当前最大值是否超过了允许的最大值
if self.maxsize is not None and len(self) > self.maxsize:
raise Exception("Full")
node = Node(value=value)
tailnode = self.tailnode()
# 最后一个节点指向新的最后节点
tailnode.next = node
# 新的最后节点指向前节点
node.prev = tailnode
# node的下一个节点指向root
node.next = self.root
# 根节点的上一个节点指向新的最后节点,形成闭环
self.root.prev = node
self.length += 1
def appendleft(self, value):
# 判断当前最大值是否超过了允许的最大值
if self.maxsize is not None and len(self) > self.maxsize:
raise Exception("Full")
node = Node(value=value)
# 如果根节点的下一个节点是自己,则证明是空的
if self.root.next is self.root:
# 新节点的下一个指向根节点
node.next = self.root
# 新节点的上一个指向根节点
node.prev = self.root
# 根节点的下一个指向新节点
self.root.next = node
# 根节点的上一个指向新节点
self.root.prev = node
else:
# 新节点的上一个节点指向根节点
node.prev = self.root
# 获取头节点
headnode = self.headnode()
# 新节点的下一个指向头节点
node.next = headnode
# 头节点的上一个指向新节点
headnode.prev = node
# 根节点的下一个指向新节点
self.root.next = node
self.length+=1
def remove(self, node):
# O(1) node is not value
if node is self.root:
return
else:
# 被删除节点的上一个节点的next指向被删除节点的下一个节点
node.prev.next = node.next
# 被删除节点的下一个节点的prev指向被删除节点的上一个节点
node.next.prev = node.prev
self.length -= 1
return node
def iter_node(self):
if self.root.next is self.root:
return
curnode = self.root.next
while curnode is not self.root:
yield curnode
curnode = curnode.next
yield curnode
def __iter__(self):
for node in self.iter_node():
yield node.value
def iter_node_reverse(self):
if self.root.next is self.root:
return
curnode = self.root.prev
while curnode is not self.root:
yield curnode
curnode = curnode.prev
yield curnode
class Deque(CirculaDoubleLinkedList):
def pop(self):
if len(self) == 0:
raise Exception("empty")
tailnade = self.tailnode()
value = tailnade.value
self.remove(tailnade)
return value
def popleft(self):
if len(self) == 0:
raise Exception("empty")
headnode = self.headnode()
value = headnode.value
self.remove(headnode)
return value
class Array(object):
def __init__(self, size=32):
self._size = size
self._items = [None] * self._size
def __getitem__(self, index):
return self._items[index]
def __setitem__(self, index, value):
self._items[index] = value
def __len__(self):
return self._size
def clear(self, value=None):
for i in range(len(self._items)):
self._items[i] = value
def __iter__(self):
for item in self._items:
yield item
class FullError(Exception):
pass
class EmptyError(Exception):
pass
class ArrayQueue(object):
def __init__(self, maxsize):
self.maxsize = maxsize
self.array = Array(maxsize)
self.head = 0
self.tail = 0
def push(self, value):
if len(self) > self.maxsize:
raise FullError("queue full")
# 对数组长度取模,保证下标能到尾部后又从头开始
self.array[self.head % self.maxsize] = value
self.head += 1
def pop(self):
value = self.array[self.tail % self.maxsize]
self.tail += 1
return value
def __len__(self):
return self.head - self.tail
标签:find 需要 长度 lan 否则 数组 error sel 更新
原文地址:https://www.cnblogs.com/guotianbao/p/12728925.html