标签:span operation opera lse 结构 ons ati else return
此只支持十以内的计算,所以如果需要通用的话还需改进!!!
from Stack import * def funcations(n): po=[] stack=Stack() for i in range(len(n)): po.append(n[i]) for token in po: if token in ‘0123456789‘: stack.push(int(token)) else: operation_1=stack.pop() operation_2=stack.pop() result=math(operation_1,operation_2,token) stack.push(int(result)) return stack.get_stack() def math(op1,op2,token): if token==‘+‘: return op1+op2 elif token==‘-‘: return op2-op1 elif token==‘*‘: return op1*op2 else: return op2/op1 if __name__ == ‘__main__‘: n=‘543*-‘ print(funcations(n))
标签:span operation opera lse 结构 ons ati else return
原文地址:https://www.cnblogs.com/ares-python/p/12826355.html