标签:charm specific ons pre ant als inpu test str
Given two strings S1 and S2, S=S1?S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1?S2 for any given strings. However, it might not be that simple to do it fast.
Each input file contains one test case. Each case consists of two lines which gives S1 and S2, respectively. The string lengths of both strings are no more than 104. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.
For each test case, print S1?S2 in one line.
They are students.
aeiou
Thy r stdnts.
给两个字符串s1,s2,计算s1-s2(在s1中删除掉s2中出现过的字符)
#include <iostream>
#include <unordered_map>
#include <string>
using namespace std;
int main() {
string s1, s2;
getline(cin, s1);
getline(cin, s2);
unordered_map<char, int> charMap;
for (int i = 0; i < s2.size(); ++i) {
charMap[s2[i]] = 1;
}
for (int i = 0; i < s1.size(); ++i) {
if (charMap[s1[i]] != 1) {
cout << s1[i];
}
}
return 0;
}
PAT 甲级 1050.String Subtraction C++/Java
标签:charm specific ons pre ant als inpu test str
原文地址:https://www.cnblogs.com/47Pineapple/p/12829032.html