获取tomcat下webapp路径

 ServletRequestAttributes att=(ServletRequestAttributes)RequestContextHolder.getRequestAttributes();
  HttpServletRequest request = att.getRequest();
  request.getSession().getServletContext().getRealPath("/") ;

String resoucePath=当前类.class.getResource("/").getPath();
String webappsDir=(new File(resoucePath,"../../")).getCanonicalPath();

Properties properties = new Properties();
InputStream in =当前类.class.getClassLoader().getResourceAsStream("demo.properties");
properties.load(in);
String webapps = properties.getProperty("path");