java 基本语法（十七）Lambda （四）构造器引用与数组引用

//Supplier中的T get()
   //Employee的空参构造器：Employee()
   @Test
   public void test1(){

       Supplier<Employee> sup = new Supplier<Employee>() {
           @Override
           public Employee get() {
               return new Employee();
           }
       };
       System.out.println("*******************");

       Supplier<Employee>  sup1 = () -> new Employee();
       System.out.println(sup1.get());

       System.out.println("*******************");

       Supplier<Employee>  sup2 = Employee :: new;
       System.out.println(sup2.get());
   }

//Function中的R apply(T t)
   @Test
   public void test2(){
       Function<Integer,Employee> func1 = id -> new Employee(id);
       Employee employee = func1.apply(1001);
       System.out.println(employee);

       System.out.println("*******************");

       Function<Integer,Employee> func2 = Employee :: new;
       Employee employee1 = func2.apply(1002);
       System.out.println(employee1);

   }

//BiFunction中的R apply(T t,U u)
   @Test
   public void test3(){
       BiFunction<Integer,String,Employee> func1 = (id,name) -> new Employee(id,name);
       System.out.println(func1.apply(1001,"Tom"));

       System.out.println("*******************");

       BiFunction<Integer,String,Employee> func2 = Employee :: new;
       System.out.println(func2.apply(1002,"Tom"));

   }

//Function中的R apply(T t)
@Test
public void test4(){
    Function<Integer,String[]> func1 = length -> new String[length];
    String[] arr1 = func1.apply(5);
    System.out.println(Arrays.toString(arr1));

    System.out.println("*******************");

    Function<Integer,String[]> func2 = String[] :: new;
    String[] arr2 = func2.apply(10);
    System.out.println(Arrays.toString(arr2));

}