标签:ova cti 类型 out swift list排序 iss 使用 接受
在开始之前,我先卖个关子提一个问题:我们现在有一个Employee员工类。
@Data
@AllArgsConstructor
public class Employee {
private Integer id;
private Integer age; //年龄
private String gender; //性别
private String firstName;
private String lastName;
}
你知道怎么对一个Employee对象组成的List集合,先按照性别字段倒序排序,再按照年龄的倒序进行排序么?如果您不知道4行代码以内的解决方案(其实是1行代码就可以实现,但笔者格式化为4行),我觉得您有必要一步步的看下去。
cities是一个字符串数组。注意london的首字母是小写的。
List<String> cities = Arrays.asList(
"Milan",
"london",
"San Francisco",
"Tokyo",
"New Delhi"
);
System.out.println(cities);
//[Milan, london, San Francisco, Tokyo, New Delhi]
cities.sort(String.CASE_INSENSITIVE_ORDER);
System.out.println(cities);
//[london, Milan, New Delhi, San Francisco, Tokyo]
cities.sort(Comparator.naturalOrder());
System.out.println(cities);
//[Milan, New Delhi, San Francisco, Tokyo, london]
同样我们可以把排序器Comparator用在Stream管道流中。
cities.stream().sorted(Comparator.naturalOrder()).forEach(System.out::println);
//Milan
//New Delhi
//San Francisco
//Tokyo
//london
在java 7我们是使用Collections.sort()接受一个数组参数,对数组进行排序。在java 8之后可以直接调用集合类的sort()方法进行排序。sort()方法的参数是一个比较器Comparator接口的实现类,Comparator接口的我们下一节再给大家介绍一下。
List<Integer> numbers = Arrays.asList(6, 2, 1, 4, 9);
System.out.println(numbers); //[6, 2, 1, 4, 9]
numbers.sort(Comparator.naturalOrder()); //自然排序
System.out.println(numbers); //[1, 2, 4, 6, 9]
numbers.sort(Comparator.reverseOrder()); //倒序排序
System.out.println(numbers); //[9, 6, 4, 2, 1]
List<Object>
排序这个功能就比较有意思了,举个例子大家理解一下。
Employee e1 = new Employee(1,23,"M","Rick","Beethovan");
Employee e2 = new Employee(2,13,"F","Martina","Hengis");
Employee e3 = new Employee(3,43,"M","Ricky","Martin");
Employee e4 = new Employee(4,26,"M","Jon","Lowman");
Employee e5 = new Employee(5,19,"F","Cristine","Maria");
Employee e6 = new Employee(6,15,"M","David","Feezor");
Employee e7 = new Employee(7,68,"F","Melissa","Roy");
Employee e8 = new Employee(8,79,"M","Alex","Gussin");
Employee e9 = new Employee(9,15,"F","Neetu","Singh");
Employee e10 = new Employee(10,45,"M","Naveen","Jain");
List<Employee> employees = Arrays.asList(e1, e2, e3, e4, e5, e6, e7, e8, e9, e10);
employees.sort(Comparator.comparing(Employee::getAge));
employees.forEach(System.out::println);
Employee(id=2, age=13, gender=F, firstName=Martina, lastName=Hengis)
Employee(id=6, age=15, gender=M, firstName=David, lastName=Feezor)
Employee(id=9, age=15, gender=F, firstName=Neetu, lastName=Singh)
Employee(id=5, age=19, gender=F, firstName=Cristine, lastName=Maria)
Employee(id=1, age=23, gender=M, firstName=Rick, lastName=Beethovan)
Employee(id=4, age=26, gender=M, firstName=Jon, lastName=Lowman)
Employee(id=3, age=43, gender=M, firstName=Ricky, lastName=Martin)
Employee(id=10, age=45, gender=M, firstName=Naveen, lastName=Jain)
Employee(id=7, age=68, gender=F, firstName=Melissa, lastName=Roy)
Employee(id=8, age=79, gender=M, firstName=Alex, lastName=Gussin)
employees.sort(Comparator.comparing(Employee::getAge).reversed());
List<Object>
排序下面这段代码先是按性别的倒序排序,再按照年龄的倒序排序。
employees.sort(
Comparator.comparing(Employee::getGender)
.thenComparing(Employee::getAge)
.reversed()
);
employees.forEach(System.out::println);
//都是正序 ,不加reversed
//都是倒序,最后面加一个reserved
//先是倒序(加reserved),然后正序
//先是正序(加reserved),然后倒序(加reserved)
细心的朋友可能注意到:我们只用了一个reversed()倒序方法,这个和SQL的表述方式不太一样。这个问题不太好用语言描述,建议大家去看一下本文对应的视频!
排序结果如下:
Employee(id=8, age=79, gender=M, firstName=Alex, lastName=Gussin)
Employee(id=10, age=45, gender=M, firstName=Naveen, lastName=Jain)
Employee(id=3, age=43, gender=M, firstName=Ricky, lastName=Martin)
Employee(id=4, age=26, gender=M, firstName=Jon, lastName=Lowman)
Employee(id=1, age=23, gender=M, firstName=Rick, lastName=Beethovan)
Employee(id=6, age=15, gender=M, firstName=David, lastName=Feezor)
Employee(id=7, age=68, gender=F, firstName=Melissa, lastName=Roy)
Employee(id=5, age=19, gender=F, firstName=Cristine, lastName=Maria)
Employee(id=9, age=15, gender=F, firstName=Neetu, lastName=Singh)
Employee(id=2, age=13, gender=F, firstName=Martina, lastName=Hengis)
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恕我直言你可能真的不会java第7篇:像使用SQL一样排序集合
标签:ova cti 类型 out swift list排序 iss 使用 接受
原文地址:https://www.cnblogs.com/zimug/p/13200981.html