PAT乙级1008 数组元素循环右移问题 (20分)

#include<stdio.h>
int main(){
    int n,k;
    scanf("%d %d",&n,&k);
    k = k%n;
    int a[1000];
    if(n == 1){
        int t;
        scanf("%d",&t);
        printf("%d",t);
    }
    else{
    
    int rear = n-1;
    int front = 0;
    for(int i = 0;i<n;i++){
        scanf("%d",&a[i]);
    }
    front+=k;
    rear = rear-k+1;
    for(int i =rear;i<n;i++){
        printf("%d ",a[i]);
    }
    int j = 0;
    while(j!=rear-1){
        printf("%d ",a[j]);
        j++;
    }
    printf("%d",a[rear-1]);}
    
    return 0;
} 

 1 #include <iostream>
 2 #include<cstdio>
 3 #include<algorithm>
 4 using namespace std;
 5 int main()
 6 {
 7     int m, n;
 8     cin >> m >> n;
 9     int a[110];
10     n = n % m;
11     for (int i = 0; i < m; i++) {
12         cin >> a[i];
13     }
14     for (int i = m - n; i < m; i++) {
15         cout << a[i]<<" ";
16     }
17     for (int i = 0; i < m - n; i++) {
18         cout << a[i];
19         if (i != m - n - 1) {
20             cout << " ";
21         }
22     }
23     return 0;
24 }