Mysql基础（十二)：sql语句执行步骤详解（一）准备工作

SELECT DISTINCT <select_list>
    FROM <left_table>
    <join_type> JOIN <right_table>
    ON <join_condition>
    WHERE <where_condition>
    GROUP BY <group_by_list>
    HAVING <having_condition>
    ORDER BY <order_by_condition>
    LIMIT <limit_number>

create database TestDB;

 CREATE TABLE table1
 (
     customer_id VARCHAR(10) NOT NULL,
     city VARCHAR(10) NOT NULL,
     PRIMARY KEY(customer_id)
 )ENGINE=INNODB DEFAULT CHARSET=UTF8;
 
 CREATE TABLE table2
 (
     order_id INT NOT NULL auto_increment,
     customer_id VARCHAR(10),
     PRIMARY KEY(order_id)
 )ENGINE=INNODB DEFAULT CHARSET=UTF8;

 INSERT INTO table1(customer_id,city) VALUES(‘163‘,‘hangzhou‘);
 INSERT INTO table1(customer_id,city) VALUES(‘9you‘,‘shanghai‘);
 INSERT INTO table1(customer_id,city) VALUES(‘tx‘,‘hangzhou‘);
 INSERT INTO table1(customer_id,city) VALUES(‘baidu‘,‘hangzhou‘);
 
 INSERT INTO table2(customer_id) VALUES(‘163‘);
 INSERT INTO table2(customer_id) VALUES(‘163‘);
 INSERT INTO table2(customer_id) VALUES(‘9you‘);
 INSERT INTO table2(customer_id) VALUES(‘9you‘);
 INSERT INTO table2(customer_id) VALUES(‘9you‘);
 INSERT INTO table2(customer_id) VALUES(‘tx‘);
 INSERT INTO table2(customer_id) VALUES(NULL);

     mysql> select * from table1;
     +-------------+----------+
     | customer_id | city     |
     +-------------+----------+
     | 163         | hangzhou |
     | 9you        | shanghai |
     | baidu       | hangzhou |
     | tx          | hangzhou |
     +-------------+----------+
     4 rows in set (0.00 sec)

 mysql> select * from table2;
 +----------+-------------+
 | order_id | customer_id |
 +----------+-------------+
 |        1 | 163         |
 |        2 | 163         |
 |        3 | 9you        |
 |        4 | 9you        |
 |        5 | 9you        |
 |        6 | tx          |
 |        7 | NULL        |
 +----------+-------------+
 7 rows in set (0.00 sec)

     SELECT a.customer_id, COUNT(b.order_id) as total_orders
     FROM table1 AS a
     LEFT JOIN table2 AS b
     ON a.customer_id = b.customer_id
     WHERE a.city = ‘hangzhou‘
     GROUP BY a.customer_id
     HAVING count(b.order_id) < 2
     ORDER BY total_orders DESC;