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适合编程小白的C语言设计习题,实现自动发牌程序!源码分享!

时间:2020-12-03 11:32:06      阅读:6      评论:0      收藏:0      [点我收藏+]

标签:nbsp   适合   height   sign   pre   data   rgba   字符数组   标识   

C语言自动发牌程序,供大家参考,具体内容如下:

一副扑克有52张牌,打桥牌时应将牌分给4个人。请设计一个程序完成自动发牌的工作。要求:黑桃用S (Spaces)表示,红桃用H (Hearts)表示,方块用D (Diamonds)表示,梅花用C (Clubs)表示。

分析:

要设置数组表现扑克牌

要设置数组表现玩家

要给扑克牌做特定标识,得到结果后玩家要知道自己手中黑桃有哪些、方块有哪些

初步想法:

设置4个字符数组保存4种梅花牌,设置4个字符数组表示4名玩家分配到的牌

每张牌随机发给4名玩家,当玩家的持牌数达到13,不再分配给该名玩家牌

代码展示:

void mycode_13()

{

srand(unsigned(time(NULL)));

/*全部牌*/

char S[13] = { 2, 3, 4, 5, 6, 7, 8, 9, T, J, Q, K, A };

char H[13] = { 2, 3, 4, 5, 6, 7, 8, 9, T, J, Q, K, A };

char D[13] = { 2, 3, 4, 5, 6, 7, 8, 9, T, J, Q, K, A };

char C[13] = { 2, 3, 4, 5, 6, 7, 8, 9, T, J, Q, K, A };

/*4个玩家*/

char player1[13], player2[13], player3[13], player4[13];

int p1 = 0, p2 = 0, p3 = 0, p4 = 0;

distribution(S, player1, player2, player3, player4, &p1, &p2, &p3, &p4);

distribution(H, player1, player2, player3, player4, &p1, &p2, &p3, &p4);

distribution(D, player1, player2, player3, player4, &p1, &p2, &p3, &p4);

distribution(C, player1, player2, player3, player4, &p1, &p2, &p3, &p4);

puts("运行结束");

for (int i = 0; i < 13; i++)

printf("%c ", player1[i]);

putchar(\n);

for (int i = 0; i < 13; i++)

printf("%c ", player2[i]);

putchar(\n);

for (int i = 0; i < 13; i++)

printf("%c ", player3[i]);

putchar(\n);

for (int i = 0; i < 13; i++)

printf("%c ", player4[i]);

}

void distribution(char * S_H_D_C, char * player1, char * player2, char * player3, char * player4, int *p1, int *p2, int *p3, int *p4)

{

static int h = 1;

int r;

int a = *p1, b = *p2, c = *p3, d = *p4;

for (int i = 0; i < 13; i++)

{

r = (rand() % 4) + 1;

while ((r == 1 && (*p1) == 13) || (r == 2 && (*p2) == 13) || (r == 3 && (*p3) == 13) || (r == 4 && (*p4) == 13))

  r = (rand() % 4) + 1;

switch (r)

{

case 1:

  player1[(*p1)++] = S_H_D_C[i];

  break;

case 2:

  player2[(*p2)++] = S_H_D_C[i];

  break;

case 3:

  player3[(*p3)++] = S_H_D_C[i];

  break;

case 4:

  player4[(*p4)++] = S_H_D_C[i];

  break;

default:

  break;

}

}

switch (h++)

{

case 1:

  printf("黑桃:\n");

  break;

case 2:

  printf("红桃:\n");

  break;

case 3:

  printf("方块:\n");

  break;

case 4:

  printf("梅花:\n");

  break;

}

printf("Player1:");

for (int i = a; i < (*p1); i++)

  printf("%c ", player1[i]);

putchar(\n);

printf("Player2:");

for (int i = b; i < (*p2); i++)

  printf("%c ", player2[i]);

putchar(\n);

printf("Player3:");

for (int i = c; i < (*p3); i++)

  printf("%c ", player3[i]);

putchar(\n);

printf("Player4:");

for (int i = d; i < (*p4); i++)

  printf("%c ", player4[i]);

putchar(\n);

}

 

以下代码保证了当某个人得到13张牌后不在得牌:

r = (rand() % 4) + 1;

while ((r == 1 && (*p1) == 13) || (r == 2 && (*p2) == 13) || (r == 3 && (*p3) == 13) || (r == 4 && (*p4) == 13))

  r = (rand() % 4) + 1;

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持我。

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适合编程小白的C语言设计习题,实现自动发牌程序!源码分享!

标签:nbsp   适合   height   sign   pre   data   rgba   字符数组   标识   

原文地址:https://www.cnblogs.com/huya-edu/p/14052668.html

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