assume cs:code,ds:data
data segment
    db ‘welcome to masm!‘
data ends
code segment
start:    mov ax,data
    mov ds,ax
    mov ax,0b800h                      ;显示缓冲区的起始地址
    mov es,ax
    mov bx,0720h                       ;设置中间行中间列的首地址

    mov si,0                           ;指向显存
    mov cx,16                          ;共16个字符,循环16次
s:    mov ax,ds:[si]
    mov ah,2h
    mov es:[bx],ax                     ;设置绿色字体
    mov ah,24h
    mov es:[bx+0a0h],ax                ;设置绿底红色
    mov ah,71h
    mov es:[bx+0a0h+0a0h],ax           ;设置白底蓝色
    inc si                             ;指向下一个字符
    add bx,2                           ;指向下一个显存单元
    loop s

    mov ax,4c00h
    int 21h
code ends
end start

assume cs:code, ds:data
data segment
    str db ‘try‘, 0
data ends

code segment
start:  
    mov ax, data
    mov ds, ax

    mov si, offset str
    mov al, 2
    call printStr

    mov ah, 4ch
    int 21h

printStr:
    push bx
    push cx
    push si
    push di

    mov bx, 0b800H
    mov es, bx
    mov di, 0
s:      mov cl, [si]
    mov ch, 0
    jcxz over
    mov ch, al
    mov es:[di], cx
    inc si
    add di, 2
    jmp s

over:   pop di
    pop si
    pop cx
    pop bx
    ret

code ends
end start

assume cs:code, ds:data
data segment
        x dw 1984
        str db 16 dup(0)
data ends

code segment
start:  
        mov ax, data
        mov ds, ax
        mov ax,0b800h
        mov es,ax
        mov ax, x
        mov di, offset str        
        mov si,0
        call num2str

        mov ah, 4ch
        int 21h

num2str:
        push ax
        push bx
        push cx
        push dx
        
        mov cx, 0
        mov bl, 10
s1:      
        div bl
        inc cx
        mov dl, ah
        push dx
        mov ah, 0
        cmp al, 0
        jne s1
s2:        
        pop dx
        or dl, 30h
        mov [di], dl
        mov dh,2
        mov es:[si],dx
        add si,2
        inc di
        loop s2
        
        pop dx
        pop cx
        pop bx
        pop ax

        ret
code ends
end start

assume cs:code, ds:data
data segment
        str db 80 dup(?)
data ends

code segment
start:  
        mov ax, data
        mov ds, ax
        mov si, 0

s1:        
        mov ah, 1
        int 21h
        mov [si], al
        cmp al, ‘#‘
        je next
        inc si
        jmp s1
next:
        mov cx, si
        mov si, 0
s2:     mov ah, 2
        mov dl, [si]
        int 21h
        inc si
        loop s2

        mov ah, 4ch
        int 21h
code ends
end start

#include <stdio.h>
int sum(int, int);

int main() {
    int a = 2, b = 7, c;

    c = sum(a, b);

    return 0;
}

int sum(int x, int y) {
    return (x + y);
}