标签:ima oat getc 选择 字符 解决 load amp info
//打印一个字符小人 #include <stdio.h> int main() { printf(" o \n"); printf("<H>\n"); printf("I I\n"); printf(" o \n"); printf("<H>\n"); printf("I I\n"); return 0; }
//打印一个字符小人 #include <stdio.h> int main() { printf(" o o\n"); printf("<H> <H>\n"); printf("I I I I\n"); return 0; }
/* 用C语言实现一个简单的算术运算程序 */ #include <stdio.h> int main() { int x, y; //定义两个整型变量,用来保存运算数据 int r1, r2, r3, r4; //定义四个整型变量,用来保存加减乘除运算结果 x = 1; y = 2; r1 = x + y; r2 = x - y; r3 = x * y; r4 = x / y; printf("r1 = %d\n", r1); printf("r2 = %d\n", r2); printf("r3 = %d\n", r3); printf("r4 = %d\n", r4); return 0; }
/* 用C语言实现一个简单的算术运算程序 */ #include <stdio.h> int main() { float x, y; //定义两个整型变量,用来保存运算数据 float r1, r2, r3, r4; //定义四个整型变量,用来保存加减乘除运算结果 x = 1; y = 2; r1 = x + y; r2 = x - y; r3 = x * y; r4 = x / y; printf("r1 = %f\n", r1); printf("r2 = %f\n", r2); printf("r3 = %f\n", r3); printf("r4 = %f\n", r4); return 0; }
#include <stdio.h> int main() { int n, r1, r2, r3, r4; n = 100; r1 = n*(n+1)/2; r2 = (n+1)*n/2; r3 = n/2*(n+1); r4 = (n+1)/2*n; printf("n = %d\n", n); printf("r1 = %d\n", r1); printf("r2 = %d\n", r2); printf("r3 = %d\n", r3); printf("r4 = %d\n", r4); return 0; }
#include <stdio.h> int main() { int n, r1, r2, r3, r4; n = 101; r1 = n*(n+1)/2; r2 = (n+1)*n/2; r3 = n/2*(n+1); r4 = (n+1)/2*n; printf("n = %d\n", n); printf("r1 = %d\n", r1); printf("r2 = %d\n", r2); printf("r3 = %d\n", r3); printf("r4 = %d\n", r4); return 0; }
#include <stdio.h> int main() { int answer; char words[5000]; printf("网课学习让一些人欢喜一些人忧.\n"); printf("1. 作为一个宅,社恐,觉得这样很好。有网络,自主学习,很ok.\n"); printf("2. 不喜,不喜,很不喜。眼睛快瞎了。脑壳有点卡...\n"); printf("3. 中间派。不知道。说不清。\n"); printf("4. 其它...\n"); printf("你的选择: "); scanf("%d", &answer); if(answer == 4) { printf("请补充说明你的想法: \n"); getchar(); gets(words); } printf("\n"); printf("当遇到问题时,你会选择:\n"); printf("1. 遇到问题,就解决问题。不懂的,搜索式学习,逐个攻破.\n"); printf("2. 遇到问题,不高兴。然后,...,没有了.\n"); printf("3. 其它...\n"); printf("你的选择: "); scanf("%d", &answer); if(answer == 1) printf(":)\n"); else if(answer == 2) printf("这样不能解决问题啊...我们选择1好不好:)\n"); else if(answer == 3) { printf("请补充说明你的想法: \n"); getchar(); gets(words); } return 0; }
#include <stdio.h> int main() { int answer; char words[5000]; printf("现在的天气让人感觉很头疼.\n"); printf("1. 作为一个南方人觉得这样很好。湿润,温和,很ok.\n"); printf("2. 不喜,不喜,很不喜潮湿。北方人向往干燥...\n"); printf("3. 中间派。不知道。说不清。\n"); printf("4. 其它...\n"); printf("你的选择: "); scanf("%d", &answer); if(answer == 4) { printf("请补充说明你的想法: \n"); getchar(); gets(words); } printf("\n"); printf("当突然降温时,你会选择:\n"); printf("1. 小问题,不用穿很厚.\n"); printf("2. 翻出衣柜里的毛衣和秋裤.\n"); printf("3. 其它...\n"); printf("你的选择: "); scanf("%d", &answer); if(answer == 1) printf("真真真硬汉:)\n"); else if(answer == 2) printf(":)\n"); else if(answer == 3) { printf("请补充说明你的想法: \n"); getchar(); gets(words); } return 0; }
标签:ima oat getc 选择 字符 解决 load amp info
原文地址:https://www.cnblogs.com/chenruiyu0167/p/14542534.html