标签:== merge nod tno node else code amp 虚拟
输入两个递增排序的链表,合并这两个链表并使新链表中的节点仍然是递增排序的。
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
//设置虚拟头结点
ListNode res = new ListNode(-1);
ListNode temp = res;
while (l1 != null && l2 != null) {
if (l1.val >= l2.val) {
temp.next = l2;
l2 = l2.next;
} else {
temp.next = l1;
l1 = l1.next;
}
temp = temp.next;
}
temp.next = l1 == null ? l2 : l1;
return res.next;
}
标签:== merge nod tno node else code amp 虚拟
原文地址:https://www.cnblogs.com/init-qiancheng/p/14618450.html