标签:pivot 最大值 heapsort 依次 冒泡 大小 video 交换 选择
# 1. 选择排序:循环找最小值,依次放在左侧 def select_sort(arr): for i in range(len(arr)-1): min_index = i for j in range(i+1, len(arr)): if arr[j] < arr[min_index]: min_index = j if i != min_index: # 交换两个元素位置 arr[i], arr[min_index] = arr[min_index], arr[i] return arr # 2. 冒泡排序 # 和插入排序相同点: 都是循环比较相邻的两个元素 # 不同点:每次循环只会和后面的一个元素比大小,不会和前面的元素比较 # 特点: 每次循环把最大值依次放在后面 def bubble_sort(arr): for i in range(1, len(arr)): for j in range(0, len(arr)-i): if arr[j] > arr[j+1]: arr[j], arr[j+1] = arr[j+1], arr[j] return arr # 3. 插入排序: # 循环比较相邻的两个元素,小的放左边;如果交换后发现左侧还有小元素,继续交换位置 def insert_sort(arr): for i in range(len(arr)): pre_index = i - 1 current = arr[i] while pre_index >= 0 and arr[pre_index] > current: arr[pre_index+1] = arr[pre_index] pre_index -= 1 arr[pre_index+1] = current return arr # 4. 希尔排序,插入排序的升级 def shell_sort(arr): meta = 2 n = len(arr) gap = int(n // meta) while gap > 0: for i in range(gap, n): current = arr[i] j = i - gap while j >= 0 and arr[j] > current: arr[j+gap] = arr[j] j -= gap arr[j+gap] = current gap = int(gap//meta) return arr # 5. 快速排序 def quick_sort(arr): if len(arr) <= 1: return arr pivot = arr[-1] # 取最后一个数作为pivot i = 0 # i记录比pivot小的数的个数 j = 0 # j用来遍历整个数列 n = len(arr) while j < n-1: if arr[j] < pivot: # 比pivot小的放前面 arr[i], arr[j] = arr[j], arr[i] i += 1 j += 1 arr[i], arr[-1] = arr[-1], arr[i] if i > 0: # 比pivot小的数据不为空, 则对其进行快速排序 arr[:i] = quick_sort(arr[:i]) if i+1 < n: # 比pivot大的数据不为空, 则对其进行快速排序 arr[i+1:] = quick_sort(arr[i+1:]) return arr # 6. 归并排序 def mergeSort(arr): if len(arr) < 2: return arr middle = len(arr) // 2 left, right = arr[0:middle], arr[middle:] return merge(mergeSort(left), mergeSort(right)) def merge(left, right): result = [] while left and right: if left[0] <= right[0]: result.append(left.pop(0)) else: result.append(right.pop(0)) while left: result.append(left.pop(0)) while right: result.append(right.pop(0)) return result # 7. 堆排序, 理解视频:https://www.bilibili.com/video/BV1Eb41147dK?from=search&seid=4983284716020974089 def heapify(arr, n, i): largest = i l = 2 * i + 1 # left = 2*i + 1 r = 2 * i + 2 # right = 2*i + 2 if l < n and arr[i] < arr[l]: largest = l if r < n and arr[largest] < arr[r]: largest = r if largest != i: arr[i], arr[largest] = arr[largest], arr[i] # 交换 heapify(arr, n, largest) def heapSort(arr): n = len(arr) # Build a maxheap. for i in range(n, -1, -1): # 递减的时候,第2个值-1表示到0结束,包括0 heapify(arr, n, i) # 一个个交换元素 for i in range(n - 1, 0, -1): arr[i], arr[0] = arr[0], arr[i] # 交换 heapify(arr, i, 0) return arr # 8.计数排序 # https://blog.csdn.net/weixin_43790276/article/details/107398262 def counting_sort(arr): if len(arr) < 2: return arr max_num = max(arr) count = [0] * (max_num + 1) # 新建一个计数列表,长度为待排序列表最大值加1。 for num in arr: count[num] += 1 # 把待排序元素值当作count列表的下标,计算每个待排序元素重复的次数 new_arr = list() for i in range(len(count)): for j in range(count[i]): # count[i]就是count列表中元素i重复的次数 new_arr.append(i) return new_arr # 9 基数排序 # coding=utf-8 def radix_sort(array): # 找出带排序元素最大数有几位 max_num = max(array) place = 1 while max_num >= 10**place: place += 1 for i in range(place): # 当i=0时,找个位的基数都有哪些;当i=1时,找十位的基数都有哪些 buckets = [[] for _ in range(10)] for num in array: radix = int(num/(10**i) % 10) buckets[radix].append(num) # 按基数对元素进行排序 j = 0 for k in range(10): for num in buckets[k]: array[j] = num j += 1 return array a = [1, 4, 9, 3, 5] # x = bubble_sort(a) #x = mergeSort(a) #x = heapSort(a) x = counting_sort(a) print(x)
标签:pivot 最大值 heapsort 依次 冒泡 大小 video 交换 选择
原文地址:https://www.cnblogs.com/regit/p/14659372.html