标签:style blog http io color ar os sp java
HTML5提供了Canvas对象,为绘图应用提供了便利.
Javascript可运行于浏览器中, 而不需要安装特定的编译器;
基于HTML5和Javascript语言, 可随时编写应用, 为算法测试带来便利.
针对TSP问题, 编写了Ant colony algorithm, 用于演示该算法, tsp_ant_colony_algorithm.html代码如下:
<html> <head> <meta charset = "utf-8" / > <title>TSP_demo</title> </head> <body> <div id="outText"> </div> <canvas id="canvas" height="550px" width="1024px"> </canvas> <script type="text/javascript"> //计时开始 t1 = new Date(); //创建"then"这个日期/时间对像 t1.setTime(t1.getTime()); //为这个对象赋值 var canvas = document.getElementById("canvas"); var canvasWidth = canvas.width; var canvasHeight = canvas.height; var context = canvas.getContext("2d"); var N = 30; //城市数量 var M = 120; //蚂蚁数量 var inittao = 1; //初始路径激素量 var tao; //[N][N]; //N*N矩阵——表示i和j间残留的激素信息量, 初始化为常熟C(各路径相等),以表示激素的挥发 var yita; //[N][N]; //N*N矩阵——表示i和j间由举例所决定的选择概率矩阵 var delta_tao; //[N][N]; //一轮循环后增加的信息素 var distant; //[N][N]; //所有城市间的距离 var tabu; //[M][N]; //禁忌表 var route; //[M][N]; //M只蚂蚁所走过的路径 var solution; //[M]; //对M只蚂蚁所走过路径的适应度评价值 var BestRoute; //[N]; //最忌路径 var BestSolution = 10000000000; //设置的极限最大路径 var alfa, beta, rou, Q; //路径激素更新数量 var NcMax; //蚁群最大迭代次数 function initMat(M, N, val) { var x = new Array(); for(var i = 0; i < M; i++) { x[i] = new Array(); for(var j = 0; j < N; j++) x[i].push(val); } return x; } function initAllMats() { tao = initMat(N, N, 0); yita = initMat(N, N, 0); delta_tao = initMat(N, N, 0); distant = initMat(N, N, 0); tabu = initMat(M, N, 0); route = initMat(M, N, -1); solution = new Array(); for(var i = 0; i < M; i++) solution[i] = 0; BestRoute = new Array(); for(var i = 0; i < N; i++) BestRoute[i] = -1; } //初始化城市的位置 function InCityXY(x, y) { for(var i = 0; i < N; i++) { x[i] = (Math.random() * 32767) % 980 + 20; y[i] = (Math.random() * 32767) % 420 + 20; } } //初始化算法参数 function initparameter() { alfa = 1; //积累的激素调节因子作用系数 beta = 5; //启发性调节因子作用系数 rou = 0.9; Q = 100; //常量 NcMax = 200; //群蚂蚁进化代数 } //取得某个路径的长度 function EvalueSolution(a) { var dist = 0; for(var i = 0; i < N-1; i++) dist += distant[a[i]][a[i+1]]; dist += distant[a[N-1]][a[0]]; return dist; } function drawCities(x, y) { for(var i = 0; i < N; i++) { context.beginPath(); context.fillStyle = "blue"; context.strokeStyle = "blue"; context.lineWidth = 1; context.font = "normal 16px Arial"; context.arc(x[i], y[i], 3, (Math.PI / 180) * 0, (Math.PI / 180) * 360, false); context.fill(); context.stroke(); context.closePath(); /* context.fillStyle = "white"; context.textAlign = "center"; context.textBaseline = "middle"; context.fillText(String(i), x[i], y[i]); */ } } function drawPath(x1, y1, x2, y2, color, width) { context.beginPath(); context.fillStyle = color; context.strokeStyle = color; context.lineWidth = width; context.moveTo(x1, y1); context.lineTo(x2, y2); context.stroke(); } //主函数 function ACA_TSP() { var NC = 0; //初始化算法参数 initparameter(); //初始化城市的位置 var x = new Array(); var y = new Array(); for(var i = 0; i < N; i++) { x.push(0); y.push(0); } //初始化城市位置 InCityXY( x, y ); //计算任意两城市间的距离 for(var i=0;i<N;i++) for(var j=i+1;j<N;j++) { distant[j][i] = Math.sqrt((x[i]-x[j])*(x[i]-x[j])+(y[i]-y[j])*(y[i]-y[j])); distant[i][j] = distant[j][i]; } // calculate the heuristic parameters var i, j, k; //初始化任意两点间的选择可能性程度=1-p //若i==j,则p=1 //否则,p=100/distant[i][j] for(i=0;i<N;i++) for(j=0;j<N;j++) { tao[i][j] = inittao; if(j != i) yita[i][j] = 100/distant[i][j]; //值越大,i到j被选择的路径概率越大; 或者说,i和j距离越近,被选择的概率越大 } //初始化M个蚂蚁走完所有城市(N)的路径 //-1表示第k只蚂蚁尚没有从当前位置走向i城市 /* for(k=0;k<M;k++) for(i=0;i<N;i++) route[k][i] =- 1; */ //初始化所有蚂蚁的禁忌表 for(k=0;k<M;k++) { route[k][0] = k % N; //随机置放蚂蚁的第一站城市点---此代码实际上没有随机摆放 tabu[k][route[k][0]] = 1; //设置禁忌表的已访问过的城市为1 } //所有蚂蚁行走NcMax趟 do { var s = 1; var partsum; var pper; var drand; //s循环N次,让每只蚂蚁走N步,走完全程 while( s < N) { for(k=0;k<M;k++) { var jrand= (Math.random() * 32767) % 3000; drand= jrand / 3001.0; partsum = 0; pper = 0; for(j=0;j<N;j++) { if(tabu[k][j]==0) partsum += Math.pow(tao[route[k][s-1]][j],alfa) * Math.pow(yita[route[k][s-1]][j],beta); } for(j=0;j<N;j++) { if(tabu[k][j]==0) pper += Math.pow(tao[route[k][s-1]][j],alfa) * Math.pow(yita[route[k][s-1]][j],beta)/partsum; if(pper > drand) break; } tabu[k][j]=1; route[k][s]=j; } s++; } // the pheromone is updated for(i=0;i<N;i++) for(var j=0;j<N;j++) delta_tao[i][j]=0; //记录最短路径及其长度 for(k=0;k<M;k++) { solution[k] = EvalueSolution(route[k]); if(solution[k] < BestSolution) { BestSolution = solution[k]; for(s=0; s<N; s++) BestRoute[s]=route[k][s]; } } //根据上一批次(M个蚂蚁)所求路径的长度信息,更新从i到j的选择概率 for(k=0;k<M;k++) { for(s=0;s<N-1;s++) delta_tao[route[k][s]][route[k][s+1]] += Q/solution[k]; delta_tao[route[k][N-1]][route[k][0]] += Q/solution[k]; } //计算NxN个节点间的转移概率,并设置最大与最小值 for(i=0;i<N;i++) for(var j=0;j<N;j++) { tao[i][j]=rou*tao[i][j]+delta_tao[i][j]; if(tao[i][j] < 0.00001) tao[i][j] = 0.00001; if(tao[i][j] > 20) tao[i][j] = 20; } //重新设置所有蚂蚁的禁忌表和路径信息 for(k=0;k<M;k++) for(var j=1;j<N;j++) { tabu[k][route[k][j]]=0; route[k][j]=-1; } NC++; } while(NC < NcMax); //output the calculating outs /* print("*针对旅行商问题的蚂蚁克隆算法*"); print("初始参数:"); print("alfa=" + alfa + ", beta=" + beta + ", rou=" + rou + ", Q=" + Q); print("蚁群探索循环次数:" + NcMax); print("最短路径是:" + BestSolution); print("最佳路径是:"); */ for(i = 0; i < N; i++) { if (i == N - 1) j = 0; else j = i + 1; var nodeA = BestRoute[i]; var nodeB = BestRoute[j]; var x1 = x[nodeA]; var y1 = y[nodeA]; var x2 = x[nodeB]; var y2 = y[nodeB]; drawPath(x1, y1, x2, y2, "black", 2); } drawCities(x, y); var out = document.getElementById("outText"); out.innerHTML = "<h1>蚂蚁克隆算法求解旅行商问题: </h1>最佳路径:<br/>"; for(i=0;i<N;i++) out.innerHTML = out.innerHTML + String(BestRoute[i]) + " "; out.innerHTML = out.innerHTML + "<br/>最短路径长度:<br/>" + BestSolution; } //调用上述函数 initAllMats(); ACA_TSP(); //结束后,取得现在时间, 并计算时间差 t2 = new Date(); //创建"then"这个日期/时间对像 var ms = t2.getTime() - t1.getTime(); var out = document.getElementById("outText"); out.innerHTML = out.innerHTML + "<br/>用时(毫秒):<br/>" + ms; </script> </body> </html>
刷新该页面, 可随机产生不同的城市点, 并计算最短路径.
实例效果如下:
需要说明的是, 算法仍需改善, 在有些其情况下,无法保障总能获得最短路径.
利用HTML5 Canvas和Javascript实现的蚁群算法求解TSP问题演示
标签:style blog http io color ar os sp java
原文地址:http://blog.csdn.net/miscclp/article/details/41169837