码迷,mamicode.com
首页 > 编程语言 > 详细

ACM&贪心算法

时间:2014-11-22 15:49:35      阅读:166      评论:0      收藏:0      [点我收藏+]

标签:http   io   ar   os   for   on   2014   amp   as   

// Source : https://oj.leetcode.com/problems/jump-game/
// Author : wizzhangquan@gmail.com
// Date : 2014-11-22

/**********************************************************************************
*
* Given an array of non-negative integers, you are initially positioned at the first index of the array.
*
* Each element in the array represents your maximum jump length at that position.
*
* Determine if you are able to reach the last index.
*
* For example:
* A = [2,3,1,1,4], return true.
*
* A = [3,2,1,0,4], return false.
*
*
**********************************************************************************/
bool canJump(int A[], int n) {
int comp=0;
for(int i=0; i<=comp && i<n; i++) {
if(i+A[i]>comp)
comp=i+A[i];
if(comp>=n-1)
return true;
}
return false;
}

ACM&贪心算法

标签:http   io   ar   os   for   on   2014   amp   as   

原文地址:http://www.cnblogs.com/wizzhangquan/p/4115152.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!