标签：leetcode
Given an array of size n, find the majority element. The majority element is the element that appears more than ?
n/2 ? times.
You may assume that the array is non-empty and the majority element always exist in the array.
Credits:
Special thanks to @ts for adding this problem and creating all test cases.
public class Solution {
public int majorityElement(int[] num) {
int last=num[0];
int cnt=1;
for(int i=1;i<num.length;i++){
if(num[i]!=last){
cnt--;
if(cnt==0){
last=num[i];
cnt=1;
}
}else{
cnt++;
}
}
return last;
}
}
https://oj.leetcode.com/problems/majority-element/
标签：leetcode
原文地址：http://blog.csdn.net/u010786672/article/details/42083347
