3 3 1 2 1 1 3 2 2 3 4 1 3 2 3 2 0 100
3 ?
AC代码:
#include <cstdio>
#include <cstring>
#include <algorithm>
#define INF 0x7f7f7f7f
using namespace std;
int map[105][105], vis[105], dis[105];
int n, m;
int prim()
{
for(int i = 1; i<=m; i++)
dis[i] = map[1][i];
dis[1] = 0; vis[1] = 1;
int sum = 0, pos;
for(int i=1; i<m; i++)
{
int tmp = INF;
for(int j=1; j<=m; j++)
{
if(!vis[j] && dis[j] < tmp)
{
tmp = dis[j];
pos = j;
}
}
if(tmp == INF) return 0;
vis[pos] = 1;
sum += tmp;
for(int j = 1; j <= m; j++)
if(!vis[j] && map[pos][j] < dis[j])
dis[j] = map[pos][j];
}
return sum;
}
int main()
{
while(scanf("%d %d", &n, &m)==2 && n)
{
int x, y, z;
memset(vis, 0, sizeof(vis));
memset(dis, 0x7f, sizeof(dis)); //这里还可以这样赋值!! 每个值的大小为0x7f7f7f7f!!
memset(map, 0x7f, sizeof(map)); //这里还可以这样赋值!! 每个值的大小为0x7f7f7f7f!!
for(int i=1; i<=n; i++)
{
scanf("%d %d %d", &x, &y, &z);
map[x][y] = map[y][x] = z;
}
int ans = prim();
if(ans) printf("%d\n", ans);
else printf("?\n");
}
return 0;
}
HDU - 1863 - 畅通工程 (最小生成树!!prim算法!!)
原文地址:http://blog.csdn.net/u014355480/article/details/42268677