第一个程序是数据生产者程序。它在需要时创建管道,然后尽可能快地向管道中写入数据。为了方便起见,本程序没有初始化缓冲区。
/*数据生产者*/
#include <unistd.h>
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <fcntl.h>
#include <limits.h>
#include <sys/types.h>
#include <sys/stat.h>
#define FIFO_NAME "/tmp/my_fifo"
#define BUFFER_SIZE PIPE_BUF
#define TEN_MEG (1024 * 1024 *10 )
int main()
{
int pipe_fd;
int res;
int open_mode = O_WRONLY;
int bytes_sent = 0;
char buffer[BUFFER_SIZE + 1];
if( -1 == access(FIFO_NAME, F_OK) ) {
res = mkfifo( FIFO_NAME, 0777 ); //创建一个FIFO
if( 0 != res ) {
fprintf( stderr, "Could not create fifo %s\n", FIFO_NAME );
exit( EXIT_FAILURE );
}
}
printf("Process %d opening FIFO O_WRONLY\n", getpid() );
pipe_fd = open( FIFO_NAME, open_mode );
printf("Process %d result %d\n", getpid(), pipe_fd);
if( -1 != pipe_fd ) {
while( bytes_sent < TEN_MEG ) {
res = write( pipe_fd, buffer, BUFFER_SIZE );
if( -1 == res ) {
fprintf( stderr, "Write error on pipe\n");
exit( EXIT_FAILURE );
}
bytes_sent += res;
}
close( pipe_fd );
}
else
exit( EXIT_FAILURE );
printf("Process %d finished\n", getpid() );
exit( EXIT_SUCCESS );
}
第二个程序是消费者程序,它从 FIFO 读取数据并丢弃它们。
/*数据消费者*/
#include <unistd.h>
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <fcntl.h>
#include <limits.h>
#include <sys/types.h>
#include <sys/stat.h>
#define FIFO_NAME "/tmp/my_fifo"
#define BUFFER_SIZE PIPE_BUF
int main()
{
int pipe_fd;
int res;
int open_mode = O_RDONLY;
int bytes_read = 0;
char buffer[BUFFER_SIZE + 1];
memset( buffer, '\0', sizeof(buffer) );
printf("Process %d opening FIFO O_RDONLY\n", getpid() );
pipe_fd = open( FIFO_NAME, open_mode );
printf("Process %d result %d\n", getpid(), pipe_fd);
if( -1 != pipe_fd ) {
do {
res = read( pipe_fd, buffer, BUFFER_SIZE );
if( -1 == res ) {
fprintf( stderr, "Write error on pipe\n");
exit( EXIT_FAILURE );
}
bytes_read += res;
}while( res>0 );
close( pipe_fd );
}
else
exit( EXIT_FAILURE );
printf("Process %d finished, %d bytes read\n", getpid(), bytes_read );
exit( EXIT_SUCCESS );
}
原文地址:http://blog.csdn.net/u014488381/article/details/42319717