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python基础的几个小练习题

时间:2015-01-09 14:12:10      阅读:241      评论:0      收藏:0      [点我收藏+]

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题目:

1、写一个程序,判断2008年是否是闰年。

2、写一个程序,用于计算2008年10月1日是这一年的第几天?(2008年1月1日是这一年的第一天)

3、(文件题)有一个“record.txt”的文件,内容如下:

# name, age, score

tom, 12, 86

Lee, 15, 99

Lucy, 11, 58

Joseph, 19, 56

第一栏为姓名(name),第二栏为年纪(age),第三栏为得分(score)

现在,写一个Python程序,

1)读取文件

2)打印如下结果:

得分低于60的人都有谁?

谁的名字以L开头?

所有人的总分是多少?

3)姓名的首字母需要大写,该record.txt是否符合此要求? 如何纠正错误的地方?

4、(练习正则表达式)有一个文件,文件名为output_1981.10.21.txt 。下面使用Python: 读取文件名中的日期时间信息,并找出这一天是周几。将文件改名为output_YYYY-MM-DD-W.txt (YYYY:四位的年,MM:两位的月份,DD:两位的日,W:一位的周几,并假设周一为一周第一天)

以下是程序清单:

  1 #-*-coding:utf-8 -*-
  2 
  3 # (1) judge leap year
  4 def judge_leap_year(n):
  5     # if n%4 == 0 and n%100 != 0:
  6     #     return True
  7     # if n%100 == 0 and n%400 == 0:
  8     if (n%4 == 0 and n%100 != 0) or (n%100 == 0 and n%400 == 0):
  9         return True
 10     else:
 11         return False
 12 
 13 # ===================================================================
 14 # (2) computing the sum days of any day(**.**.**)
 15 def compute_year_counts(datestr):
 16     # deal with these case:
 17     # 2012.12.2
 18     # 2012/12/2
 19     # 2012-12-2
 20     if datestr.find(.) > 0: date = datestr.split(.)
 21     if datestr.find(/) > 0: date = datestr.split(/)
 22     if datestr.find(-) > 0: date = datestr.split(-)
 23 
 24     year = int(date[0])
 25     month = int(date[1])
 26     day = int(date[2])
 27     if (month < 1 or month > 12):
 28         print "the error month!"
 29         return -1
 30     if (day > 31):
 31         print "the error day!"
 32         return -1
 33 
 34     days = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
 35 
 36     # nDays = 0
 37     # i = 1
 38     # while i < month:
 39     #     nDays += days[i-1]
 40     #     i = i + 1
 41     nDays = sum(days[i] for i in range(0, month - 1))
 42     if (judge_leap_year(year)):
 43         nDays += 1
 44     return nDays + day 
 45 
 46 datestring = raw_input("input the datetime info:-->")
 47 print compute_year_counts(datestring)
 48 
 49 # ===================================================================
 50 # (3) read and write file: use class if perfect!
 51 class UserProfier(object):
 52     def __init__(self, name, age, score):
 53         self.name = name
 54         self.age = age 
 55         self.score = score
 56 
 57 def read_file_and_anlysis(filetext):
 58     line_read = []
 59     user_scores = []
 60     has_invalid_name = False #the invalid name
 61 
 62     for line in filetext:
 63         if not line.startswith(#) and len(line.strip()) != 0:
 64             if line[0].islower():
 65                 line = line[0].upper() + line[1:]
 66                 has_invalid_name = True
 67             cur = line.strip().split(, )
 68             user_scores.append(UserProfier(cur[0], int(cur[1]), int(cur[2])))
 69             line_read.append(line)
 70     # print the file
 71     print "print the file"
 72     for i in line_read:
 73         print i
 74     # statistic the score < 60
 75     print "users whose score lower 60:"
 76     for scores in filter(lambda s: s.score < 60 , user_scores):
 77         print scores.name
 78     # statistic the begin of name which is ‘L‘
 79     print "users whose name‘s begin is ‘L‘:"
 80     for names in filter(lambda s: s.name.startswith(L), user_scores):
 81         print names.name
 82     # statistic the total scores of all one
 83     print "the total scores of everyone:"
 84     allscores = map(lambda s:s.score, user_scores)
 85     print allscores
 86     print reduce(lambda x, y: x+y, allscores, 0)
 87 
 88 # open the file 
 89 with open("record.txt") as f:
 90     read_file_and_anlysis(f)
 91 
 92 # ===================================================================
 93 # (4) the useful example of regular expression
 94 import os, re, datetime
 95 
 96 filename = "output_1981.10.21.txt"
 97 
 98 date_time = re.search("(?P<year>\d{4})\.(?P<month>\d{2})\.(?P<day>\d{2})\.", filename)
 99 
100 year = date_time.group(year)
101 month = date_time.group(month)
102 day = date_time.group(day)
103 
104 print year, month, day
105 date = datetime.date(int(year), int(month), int(day))
106 w = date.weekday() + 1
107 W = str(w)
108 os.rename(filename, "output_"+year+-+month+-+day+-+str(w)+".txt")

 

python基础的几个小练习题

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原文地址:http://www.cnblogs.com/bakari/p/4213039.html

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