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题目：
Given numRows, generate the first numRows of Pascal‘s triangle.
For example, given numRows = 5,
Return
[
[1],
[1,1],
[1,2,1],
[1,3,3,1],
[1,4,6,4,1]
]
代码：oj测试通过 Runtime: 46 ms
1 class Solution: 2 # @return a list of lists of integers 3 def generate(self, numRows): 4 if numRows < 1: 5 return [] 6 pascal = [] 7 first_row = [1] 8 pascal.append(first_row) 9 for i in range(1,numRows): 10 tmp = [] 11 tmp.append(1) 12 for j in range(len(pascal[i-1])): 13 if j == len(pascal[i-1])-1: 14 tmp.append(1) 15 else: 16 tmp.append(pascal[i-1][j] + pascal[i-1][j+1]) 17 pascal.append(tmp) 18 return pascal
思路：
排除几个special case
然后把pascal写成如下的形式，比较容易写代码：
[1]
[1,1]
[1,2,1]
[1,3,3,1]
[1,4,6,4,1]
leetcode 【 Pascal's Triangle 】python 实现
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原文地址：http://www.cnblogs.com/xbf9xbf/p/4229949.html
