【Java练习】6-2.GPS数据处理

 1 package mian;
 2 
 3 import java.util.Scanner;
 4 
 5 public class Main {
 6 
 7     public static void main(String[] args) {
 8         // TODO Auto-generated method stub
 9         Scanner in = new Scanner(System.in);
10         String s = null, s2 = null;
11         int cak;
12         int B, UTC;
13         boolean flag = true;
14         do {
15             s = in.next();
16             if(s.equals("END")) {//结束判断
17                 flag = false;
18             }
19             else if(s.indexOf("$GPRMC") == 0) {//1.$GPRMC语句判断
20                 cak = s.charAt(s.indexOf(1));
21                 for(int i = 2; i < s.indexOf(‘*‘); ++i) {
22                     cak ^= s.charAt(i);//计算异或值
23                 }
24                 cak %= 65536;
25                 if(cak == Integer.parseInt(s.substring(s.indexOf(‘*‘)+1), 16) && s.indexOf(",A,") != -1) {//判断异或值是否正确，以及与是否定位。
26                     s2 = " " + s;//新建字符串保存于s2
27                 }
28             }
29         } while(flag);
30         s = s2.substring(1);//得到正确的字符串
31         UTC = Integer.parseInt(s.substring(7, 13));//得到UTC值
32         B = UTC + 80000;//得到北京时间值
33         s = ":" + String.valueOf(B).substring(String.valueOf(B).length()-2);//秒数转化成字符串，此时包含前导
34         s = ":" + String.valueOf(B).substring(String.valueOf(B).length()-4 , String.valueOf(B).length()-2) + s;//分数转化成字符串
35         B /= 10000;
36         if(B >= 24) {
37             B -= 24;
38         }
39         if(B >= 10) {
40             s = String.valueOf(B) + s;
41         }
42         else if(B < 10 && B >= 0) {
43             s = "0" + String.valueOf(B) + s;
44         }
45         System.out.println(s);
46         in.close();
47     }
48 
49 }