Problem:
You are given a binary tree in which each node contains a value. Design an algorithm to print all paths which sum to a given value. The path does not need to start or end at the root or a leaf.
This is actually an level order traversal problem. We need to store the level value together and then calculate the summation of level up and level down together.
Here is the same test case as above tree problems in cc150.
class ListNode: def __init__(self,val): self.val=val self.next=None class TreeNode: def __init__(self,val): self.val=val self.left=None self.right=None root=TreeNode(0) root.left=TreeNode(1) root.right=TreeNode(2) root.left.left=TreeNode(3) root.left.right=TreeNode(4) root.left.left.left=TreeNode(5) root.right.left=TreeNode(8) root.right.right=TreeNode(9)
def levelorder(root,solution,path,level,target): if root==None: return path[level]=root.val temp=[] i=level while i>=0: temp=temp+[path[i]] if sum(temp)==target: solution.append(temp) i-=1 levelorder(root.left,solution,path,level+1,target) levelorder(root.right,solution,path,level+1,target) def main(): solution=[] path={} levelorder(root,solution,path,0,4) print solution if __name__=="__main__": main()
craking the code interview all path sum python
原文地址:http://blog.csdn.net/hyperbolechi/article/details/42962337