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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1542 Accepted Submission(s): 769
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<cstdlib>
#include<algorithm>
using namespace std;
int tt,n,mark[100010],link[100010],vis[100010];
struct node
{
int x,y;
}e[100010];
bool dfs(int t)
{
for(int i=e[t].x;i<=e[t].y;i++)
{
if(mark[i]==-1)
{
mark[i]=1;
if(link[i]==-1||dfs(link[i]))
{
link[i]=t;
vis[t]=1;
return true;
}
}
}
return false;
}
int main()
{
scanf("%d",&tt);
while(tt--)
{
memset(vis,0,sizeof(vis));
int sum=0;
scanf("%d",&n);
for(int i=1;i<=n;i++)
scanf("%d%d",&e[i].x,&e[i].y);
memset(link,-1,sizeof(link));
for(int i=n;i>=1;i--)
{
memset(mark,-1,sizeof(mark));
if(dfs(i))
sum++;
}
printf("%d\n",sum);
for(int i=1;i<=n;i++)
{
if(vis[i])
{
if(sum>1)
printf("%d ",i);
else
printf("%d\n",i);
sum--;
}
}
}
return 0;
}
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原文地址:http://www.cnblogs.com/a972290869/p/4247889.html