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Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 9050 | Accepted: 3604 |
Description
Input
Output
Sample Input
2 10 15 5 1 3 5 10 7 4 9 2 8 5 11 1 2 3 4 5
Sample Output
2 3
#include <cstdio> #include <cmath> #include <cstring> #include <ctime> #include <iostream> #include <algorithm> #include <set> #include <vector> #include <sstream> #include <queue> #include <typeinfo> #include <fstream> typedef long long ll; using namespace std; //freopen("D.in","r",stdin); //freopen("D.out","w",stdout); #define sspeed ios_base::sync_with_stdio(0);cin.tie(0) #define maxn 100001 const int inf=0x7fffffff; //无限大 int a[maxn]; int main() { int t; cin>>t; while(t--) { int n,s; cin>>n>>s; for(int i=0;i<n;i++) { cin>>a[i]; } ll sum=a[0]; int st=0,en=0; int minn=inf; while(en!=n&&st<=en) { //cout<<st<<" "<<en<<" "<<sum<<endl; if(sum>=s) { minn=min(minn,en-st+1); sum-=a[st]; st++; } if(sum<s) { en++; sum+=a[en]; } } if(minn==inf) cout<<"0"<<endl; else cout<<minn<<endl; } return 0; }
POJ 3061 Subsequence 尺取法,一个屌屌的O(n)算法
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原文地址:http://www.cnblogs.com/qscqesze/p/4248633.html