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比较日期大小是任何编程语言都会经常遇到的问题,再iOS编程中,通常用NSDate对象来存储一个时间(包括日期和时间、时区),而且 NSDate类提供了compare方法来进行时间的比较,但有时不想那么精确的知道两个日期的大小(默认会比较到秒),可以用下面的实现方法:
+(int)compareOneDay:(NSDate *)oneDay withAnotherDay:(NSDate *)anotherDay { NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; [dateFormatter setDateFormat:@"dd-MM-yyyy"]; NSString *oneDayStr = [dateFormatter stringFromDate:oneDay]; NSString *anotherDayStr = [dateFormatter stringFromDate:anotherDay]; NSDate *dateA = [dateFormatter dateFromString:oneDayStr]; NSDate *dateB = [dateFormatter dateFromString:anotherDayStr]; NSComparisonResult result = [dateA compare:dateB]; NSLog(@"date1 : %@, date2 : %@", oneDay, anotherDay); if (result == NSOrderedDescending) { //NSLog(@"Date1 is in the future"); return 1; } else if (result == NSOrderedAscending){ //NSLog(@"Date1 is in the past"); return -1; } //NSLog(@"Both dates are the same"); return 0; }
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原文地址:http://www.cnblogs.com/allanliu/p/4250608.html