【leetcode SQL】Employees Earning More Than Their Managers

标签：leetcode   sql   

The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.

+----+-------+--------+-----------+
| Id | Name  | Salary | ManagerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | NULL      |
| 4  | Max   | 90000  | NULL      |
+----+-------+--------+-----------+

Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.

+----------+
| Employee |
+----------+
| Joe      |
+----------+

解决方案如下：

# Write your MySQL query statement below
Select a.Name as Employee 
from Employee a inner join Employee b on a.ManagerId=b.Id
where a.Salary>b.Salary

【leetcode SQL】Employees Earning More Than Their Managers

标签：leetcode   sql   

原文地址：http://blog.csdn.net/exceptional_derek/article/details/43375217