标签:前端 javascript ajax php 跨域
写js时总是会遇到跨域请求的问题,现在了解了两种方法,记录之:
1)使用$.ajax,但是返回数据类型要设置为jsonp,示例:
$.ajax({
type: 'get',
contentType: "application/json; charset=utf-8",
url: "http://localhost:8080/aqi/getCityList.php",
dataType: 'jsonp',
headers: {
Accept: "application/json",
"Access-Control-Allow-Origin": "*"
},
crossDomain: true,
async: false,
jsonp: "callback",//传递给请求处理程序或页面的,用以获得jsonp回调函数名的参数名(默认为:callback)
jsonpCallback:"success_jsonpCallback",//自定义的jsonp回调函数名称,默认为jQuery自动生成的随机函数名
success:function(json){
getCityListSuccess(json);
},
error: function (data, textStatus, errorThrown) {
console.log("error" + ' ' + JSON.stringify(data) + textStatus + errorThrown);
}
});PHP端的代码为:<?php
header("Content-Type: text/html;charset=utf-8");
$db_name="aqidata.db";
$conn = new sqlite3($db_name);
$callback = $_GET['callback'];
$resultarray=array();
<span style="white-space:pre"> </span>$sql = "select * from 'city' where 1=1 order by id";
<span style="white-space:pre"> </span>$result = $conn->query($sql);
<span style="white-space:pre"> </span>$i=0;
<span style="white-space:pre"> </span>while ($row = $result->fetchArray(SQLITE3_ASSOC)) {
<span style="white-space:pre"> </span>$resultarray[$i]=$row;
<span style="white-space:pre"> </span>$i++;
<span style="white-space:pre"> </span>}
echo $callback.'('.json_encode($resultarray).')';
?>注意:1、ajax中要指定jsonp参数,然后后端要把回调函数名称写入到返回值中。
我参考的博文是:http://www.cnblogs.com/xcxc/p/3729660.html
2)用$.getJSON,这个函数就支持跨域调用。
$.getJSON("http://localhost:8080/aqi/getCityList.php",function(json){
getCityListSuccess(json);
});但是后端代码(php)要加入:header("Access-Control-Allow-Origin:*");不然会报错:No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'null' is therefore not allowed access.我参考的博文是:http://blog.163.com/lvshutao@126/blog/static/164637467201442253942499/?latestBlog
标签:前端 javascript ajax php 跨域
原文地址:http://blog.csdn.net/ldldong/article/details/43404677