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using System;
using System.Collections.Generic;
using System.Linq;
namespace GraphAlgorithmTesting
{
class Program
{
static void Main(string[] args)
{
Graph g = new Graph(9);
g.AddEdge(0, 1, 4);
g.AddEdge(0, 7, 8);
g.AddEdge(1, 2, 8);
g.AddEdge(1, 7, 11);
g.AddEdge(2, 3, 7);
g.AddEdge(2, 5, 4);
g.AddEdge(8, 2, 2);
g.AddEdge(3, 4, 9);
g.AddEdge(3, 5, 14);
g.AddEdge(5, 4, 10);
g.AddEdge(6, 5, 2);
g.AddEdge(8, 6, 6);
g.AddEdge(7, 6, 1);
g.AddEdge(7, 8, 7);
Console.WriteLine();
Console.WriteLine("Graph Vertex Count : {0}", g.VertexCount);
Console.WriteLine("Graph Edge Count : {0}", g.EdgeCount);
Console.WriteLine();
Console.WriteLine("Is there cycle in graph: {0}", g.HasCycle());
Console.WriteLine();
Edge[] mst = g.Kruskal();
Console.WriteLine("MST Edges:");
foreach (var edge in mst)
{
Console.WriteLine("\t{0}", edge);
}
Console.ReadKey();
}
class Edge
{
public Edge(int begin, int end, int weight)
{
this.Begin = begin;
this.End = end;
this.Weight = weight;
}
public int Begin { get; private set; }
public int End { get; private set; }
public int Weight { get; private set; }
public override string ToString()
{
return string.Format(
"Begin[{0}], End[{1}], Weight[{2}]",
Begin, End, Weight);
}
}
class Subset
{
public int Parent { get; set; }
public int Rank { get; set; }
}
class Graph
{
private Dictionary<int, List<Edge>> _adjacentEdges
= new Dictionary<int, List<Edge>>();
public Graph(int vertexCount)
{
this.VertexCount = vertexCount;
}
public int VertexCount { get; private set; }
public IEnumerable<int> Vertices { get { return _adjacentEdges.Keys; } }
public IEnumerable<Edge> Edges
{
get { return _adjacentEdges.Values.SelectMany(e => e); }
}
public int EdgeCount { get { return this.Edges.Count(); } }
public void AddEdge(int begin, int end, int weight)
{
if (!_adjacentEdges.ContainsKey(begin))
{
var edges = new List<Edge>();
_adjacentEdges.Add(begin, edges);
}
_adjacentEdges[begin].Add(new Edge(begin, end, weight));
}
private int Find(Subset[] subsets, int i)
{
// find root and make root as parent of i (path compression)
if (subsets[i].Parent != i)
subsets[i].Parent = Find(subsets, subsets[i].Parent);
return subsets[i].Parent;
}
private void Union(Subset[] subsets, int x, int y)
{
int xroot = Find(subsets, x);
int yroot = Find(subsets, y);
// Attach smaller rank tree under root of high rank tree
// (Union by Rank)
if (subsets[xroot].Rank < subsets[yroot].Rank)
subsets[xroot].Parent = yroot;
else if (subsets[xroot].Rank > subsets[yroot].Rank)
subsets[yroot].Parent = xroot;
// If ranks are same, then make one as root and increment
// its rank by one
else
{
subsets[yroot].Parent = xroot;
subsets[xroot].Rank++;
}
}
public bool HasCycle()
{
Subset[] subsets = new Subset[VertexCount];
for (int i = 0; i < subsets.Length; i++)
{
subsets[i] = new Subset();
subsets[i].Parent = i;
subsets[i].Rank = 0;
}
// Iterate through all edges of graph, find subset of both
// vertices of every edge, if both subsets are same,
// then there is cycle in graph.
foreach (var edge in this.Edges)
{
int x = Find(subsets, edge.Begin);
int y = Find(subsets, edge.End);
if (x == y)
{
return true;
}
Union(subsets, x, y);
}
return false;
}
public Edge[] Kruskal()
{
// This will store the resultant MST
Edge[] mst = new Edge[VertexCount - 1];
// Step 1: Sort all the edges in non-decreasing order of their weight
// If we are not allowed to change the given graph, we can create a copy of
// array of edges
var sortedEdges = this.Edges.OrderBy(t => t.Weight);
var enumerator = sortedEdges.GetEnumerator();
// Allocate memory for creating V ssubsets
// Create V subsets with single elements
Subset[] subsets = new Subset[VertexCount];
for (int i = 0; i < subsets.Length; i++)
{
subsets[i] = new Subset();
subsets[i].Parent = i;
subsets[i].Rank = 0;
}
// Number of edges to be taken is equal to V-1
int e = 0;
while (e < VertexCount - 1)
{
// Step 2: Pick the smallest edge. And increment the index
// for next iteration
Edge nextEdge;
if (enumerator.MoveNext())
{
nextEdge = enumerator.Current;
int x = Find(subsets, nextEdge.Begin);
int y = Find(subsets, nextEdge.End);
// If including this edge does‘t cause cycle, include it
// in result and increment the index of result for next edge
if (x != y)
{
mst[e++] = nextEdge;
Union(subsets, x, y);
}
else
{
// Else discard the nextEdge
}
}
}
return mst;
}
}
}
}
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原文地址：http://www.cnblogs.com/dmdj/p/4271000.html
