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C++程序设计实践指导1.9统计与替换字符串中的关键字改写要求实现

时间:2015-02-07 14:19:52      阅读:198      评论:0      收藏:0      [点我收藏+]

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改写要求1:将字符数组str改为字符指针p,动态开辟存储空间

改写要求2:增加统计关键字个数的函数void CountKeyWords()

改写要求3: 增加替换函数void FindKeyWords()

#include <cstdlib>
#include <iostream>
#include <string>
using namespace std;

class WORDNUM
{
      char *p;
      double c;
      public:
             WORDNUM(char *s)
             {
                 p=new char[strlen(s)];
                 strcpy(p,s);
                 c=0;
             }
             void process();
             void CountKeyWords(string key[],int len);
             void FindKeyWords(string key[],string swapkey[],int len);
             void print()
             {
                  char* r=new char[strlen(p)];
                  strcpy(r,p);
                  while(*r!=\0)
                  cout<<*(r++);
                  cout<<endl;
                  cout<<"num="<<c<<endl;
             }
};

void WORDNUM::CountKeyWords(string key[],int len)
{
     int i=len;
     while(i)
     {
     double sameword=0;
     char* r=new char[strlen(p)];
     strcpy(r,p);
     char* q=new char[key[i-1].length()];
     strcpy(q,key[i-1].c_str());
     char* find=strstr(r,q);
     while(find)
     {       
            memset(find,  , strlen(q));
            sameword++;
            find=strstr(find,q);
    
     }
      
     cout<<key[i-1]<<"的个数为:"<<sameword<<"占全部字符"<<(sameword/c)*100<<"%"<<endl;
     i--;
     }
}

void WORDNUM::FindKeyWords(string key[],string swapkey[],int len)
{
   int i=len;
   string temp;
   temp=p;
   int pos=temp.find(key[i-1]);
   while(i)
   {
     while(pos!=-1)
     {       
            temp.replace(pos,key[i-1].length(),swapkey[i-1]);
            pos=temp.find(key[i-1]);
    
     }
     i--; 
   } 
   memset(p,0,sizeof(p));
   strcpy(p,temp.c_str());
}

void WORDNUM::process()
{
     int word=1;
     int len;
     len=strlen(p);
     char* r=new char[strlen(p)];
     strcpy(r,p);
     for(int i=0;i<len;i++)
     {
             if(((r[i]>=a&&r[i]<=z)||(r[i]>=A&&r[i]<=Z))&&word)
             {
                   c++;
                   word=0;
             }
             else if(r[i]== )
                      word=1;
     }
}

int main(int argc, char *argv[])
{
    string key[2]={"nice","girl"};
    string swapkey[2]={"ugly","boy"};
    int len=sizeof(key)/sizeof(key[0]);
    string str="She is a nice nice girl girl girl hi";
    char* split=new char[strlen(str.c_str())];
    strcpy(split,str.c_str());
    WORDNUM w(split);
    w.process();        
    w.CountKeyWords(key,len);
    w.print();
    w.FindKeyWords(key,swapkey,len);
    w.print();
    system("PAUSE");
    return EXIT_SUCCESS;
}

 

C++程序设计实践指导1.9统计与替换字符串中的关键字改写要求实现

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原文地址:http://www.cnblogs.com/c5395348/p/4278714.html

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