算法导论11.2散列表Hash tables链式法解决碰撞

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/*
 * IA_11.2ChainedHash.cpp
 *
 *  Created on: Feb 12, 2015
 *      Author: sunyj
 */

#include <stdint.h>
#include <iostream>
#include <string.h>
// CHAINED-HASH-INSERT(T, x)
// insert x at the head of list T[h(x.key)]

// CHAINED-HASH-SEARCH(T, k)
// search for an element with key k in list T[h(k)]

// CHAINED-HASH-DELETE(T, x)
// delete x from the list T[h(x.key)]

class ListNode {
public:
    ListNode() : key(0), data(0), prev(nullptr), next(nullptr)
    {
    	std::cout << "ListNode()" << std::endl;
    }
    ListNode(int64_t const k, int64_t d) : key(k), data(d), prev(nullptr), next(nullptr) { }

    int64_t key;
    int64_t data;
    ListNode* prev;
    ListNode* next;
};

// LIST-SEARCH(L, k)
// x = L.nil.next
// while ( x != L.nil and x.key != k)
//     x = x.next
// return x

// LIST-INSERT(L, x)
// x.next = L.nil.next
// L.nil.next.prev = x
// L.nil.next = x
// x.prev = L.nil

// LIST-DELETE(L, x)
// x.prev.next = x.next
// x.next.prev = x.prev

class LinkedList {
public:
    LinkedList() : nil(&m_nil)
    {
    	std::cout << "LinkedList()" << std::endl;
        nil->prev = nil;
        nil->next = nil;
        nil->data = -1; //
    }
    ListNode* search(int64_t const k)
    {
        ListNode* x = nil->next;
        while (x != nil && k != x->key)
        {
            x = x->next;
        }
        return x;
    }
    void insert(ListNode* x)
    {
        x->next         = nil->next;
        nil->next->prev = x;
        nil->next       = x;
        x->prev         = nil;
    }
    void del(ListNode* x)
    {
        x->prev->next = x->next;
        x->next->prev = x->prev;
    }
    void print()
    {
        ListNode* x = nil->next;
        while (nil != x)
        {
            std::cout << x->key << " ";
            x = x->next;
        }
        std::cout << std::endl;
    }
private:
    ListNode  m_nil; // empty list has noe node, pointer nill points to it.
    ListNode* nil;
};

class ChainedHashTable {
public:
	ChainedHashTable(int64_t const n) : size(n)
    {
        data = new LinkedList[n]();
    }
    ~ChainedHashTable() {}
    int64_t HashFunc(int64_t const key)
    {
    	return key % size;
    }
    ListNode* search(int64_t const key)
    {
    	return data[HashFunc(key)].search(key);
    }
    void insert(ListNode* x)
    {
    	(data[HashFunc(x->key)]).insert(x);
    }
    void del(ListNode* x)
    {
    	data[HashFunc(x->key)].del(x);
    }
    void print(int64_t key)
    {
    	data[HashFunc(key)].print();
    }
private:
    LinkedList* data;
    int64_t size;
};

int main()
{
	LinkedList a;
	/*
	 * A prime not too close to an exact power of 2 is often a good choice for m. For
example, suppose we wish to allocate a hash table, with collisions resolved by
chaining, to hold roughly n = 2000 character strings, where a character has 8 bits.
We don‘t mind examining an average of 3 elements in an unsuccessful search, and
so we allocate a hash table of size m = 701. We could choose 701 because
it is a prime near 2000=3 but not near any power of 2.
	 */
    ChainedHashTable table(701); // The division method,

    ListNode node1(1, 100);
    ListNode node4(4, 400);
    ListNode node16(16, 1600);
    ListNode node9(9, 900);
    table.insert(&node1);
    table.insert(&node4);
    table.insert(&node16);
    table.insert(&node9);
    table.print(4);
    ListNode node25(25, 2500);
    table.insert(&node25);
    table.print(16);
    table.del(&node1);
    table.print(9);
    ListNode* tmp;
    tmp = table.search(9);
    table.del(tmp);
    table.print(9);
    return 0;
}

算法导论11.2散列表Hash tables链式法解决碰撞

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原文地址：http://www.cnblogs.com/sunyongjie1984/p/4287759.html