用C++实现一个不能被继承的类

标签：c++   继承   

构造函数是实现继承的关键，子类对象在构造时，首先调用父类的构造函数，在调用自己的构造函数。

#include <iostream>

using namespace std;

template <typename T>
class A
{
    public:
        friend T;
    private:
        A(){}
        ~A(){}
};

class B:virtual public A <B>
{
    public:
        B(){}
        ~B(){}
};

//class C:virtual public B
//{
//  public:
//      C(){}
//      ~C(){}
//};

int main()
{
    B b;
//  C c;

template.cpp: In constructor ‘C::C()’:
template.cpp:11:3: error: ‘A<T>::A() [with T = B]’ is private
   A(){}
   ^
template.cpp:25:6: error: within this context
   C(){}
      ^
template.cpp:12:3: error: ‘A<T>::~A() [with T = B]’ is private
   ~A(){}
   ^
template.cpp:25:6: error: within this context
   C(){}
      ^
template.cpp: In destructor ‘C::~C()’:
template.cpp:12:3: error: ‘A<T>::~A() [with T = B]’ is private
   ~A(){}
   ^
template.cpp:26:7: error: within this context
   ~C(){}
       ^

用C++实现一个不能被继承的类

标签：c++   继承   

原文地址：http://blog.csdn.net/xueyuehanzhu123/article/details/44079145