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在Linux内核源代码情景分析-从路径名到目标节点,一文中path_walk代码中,err = permission(inode, MAY_EXEC)当前进程是否可以访问这个节点,代码如下:
int permission(struct inode * inode,int mask) { if (inode->i_op && inode->i_op->permission) { int retval; lock_kernel(); retval = inode->i_op->permission(inode, mask); unlock_kernel(); return retval; } return vfs_permission(inode, mask); }在ext2_read_inode中,i_op可以设置为ext2_file_inode_operations,ext2_dir_inode_operations,ext2_fast_symlink_inode_operations,page_symlink_inode_operations,均没有permission指针。所以执行vfs_permission,代码如下:
int vfs_permission(struct inode * inode,int mask) { int mode = inode->i_mode; if ((mask & S_IWOTH) && IS_RDONLY(inode) && (S_ISREG(mode) || S_ISDIR(mode) || S_ISLNK(mode))) return -EROFS; //如果要求的写文件,并且是只读系统,而且是常规文件,目录,或者链接时,返回-EROFS,表示不能访问 if ((mask & S_IWOTH) && IS_IMMUTABLE(inode)) //Nobody gets write access to an immutable file return -EACCES; if (current->fsuid == inode->i_uid)//如果当前进程的fsuid和inode结构的i_uid相等,那么应该比较mode中S_IRUSR、S_IWUSR、S_IXUSR位 mode >>= 6; else if (in_group_p(inode->i_gid))//如果当前进程的fsgid和inode结构的i_gid相等,那么应该比较mode中S_IRGRP、S_IWGRP、S_IXGRP位 mode >>= 3; if (((mode & mask & S_IRWXO) == mask) || capable(CAP_DAC_OVERRIDE))//mask相当于要求,mode是现有的当前用户可以访问的权限,如果相等就返回0。假如不相等,如果当前进程得到了授权,允许其CAP_DAC_OVERRIDE,即可以凌驾于文件系统的访问权限控制机制DAC之上。 return 0; /* read and search access */ if ((mask == S_IROTH) || (S_ISDIR(inode->i_mode) && !(mask & ~(S_IROTH | S_IXOTH)))) if (capable(CAP_DAC_READ_SEARCH)) return 0; return -EACCES; }
其中mask为:
#define MAY_EXEC 1 #define MAY_WRITE 2 #define MAY_READ 4inode->i_mode为:
用于对三种不同用户的访问权限:
#define S_IRWXU 00700 #define S_IRUSR 00400 #define S_IWUSR 00200 #define S_IXUSR 00100 #define S_IRWXG 00070 #define S_IRGRP 00040 #define S_IWGRP 00020 #define S_IXGRP 00010 #define S_IRWXO 00007 #define S_IROTH 00004 #define S_IWOTH 00002 #define S_IXOTH 00001
参考这张图就好理解了。
还有三个标志位,是一个状态占一个位:
#define S_ISUID 0004000 #define S_ISGID 0002000 #define S_ISVTX 0001000现在16位只剩下4位了,表示文件类型,要为每种文件类型都分配一个标志位就不够了,所以表示文件的类型的这4位是编码的。
#define S_IFMT 00170000 #define S_IFSOCK 0140000 #define S_IFLNK 0120000 #define S_IFREG 0100000 #define S_IFBLK 0060000 #define S_IFDIR 0040000 #define S_IFCHR 0020000 #define S_IFIFO 0010000
capable,代码如下:
static inline int capable(int cap) { #if 1 /* ok now */ if (cap_raised(current->cap_effective, cap)) #else if (cap_is_fs_cap(cap) ? current->fsuid == 0 : current->euid == 0) #endif { current->flags |= PF_SUPERPRIV; return 1; } return 0; }
#define cap_raised(c, flag) (cap_t(c) & CAP_TO_MASK(flag))
#define cap_t(x) (x)
#define CAP_TO_MASK(x) (1 << (x))
current->cap_effective是在sys_execve->do_execve->prepare_binprm初始设置的。
int prepare_binprm(struct linux_binprm *bprm) { int mode; struct inode * inode = bprm->file->f_dentry->d_inode; mode = inode->i_mode; /* Huh? We had already checked for MAY_EXEC, WTF do we check this? */ if (!(mode & 0111)) /* with at least _one_ execute bit set */ return -EACCES; if (bprm->file->f_op == NULL) return -EACCES; bprm->e_uid = current->euid; bprm->e_gid = current->egid; if(!IS_NOSUID(inode)) { /* Set-uid? */ if (mode & S_ISUID) bprm->e_uid = inode->i_uid; /* Set-gid? */ /* * If setgid is set but no group execute bit then this * is a candidate for mandatory locking, not a setgid * executable. */ if ((mode & (S_ISGID | S_IXGRP)) == (S_ISGID | S_IXGRP)) bprm->e_gid = inode->i_gid; } /* We don‘t have VFS support for capabilities yet */ cap_clear(bprm->cap_inheritable); cap_clear(bprm->cap_permitted); cap_clear(bprm->cap_effective); /* To support inheritance of root-permissions and suid-root * executables under compatibility mode, we raise all three * capability sets for the file. * * If only the real uid is 0, we only raise the inheritable * and permitted sets of the executable file. */ if (!issecure(SECURE_NOROOT)) { if (bprm->e_uid == 0 || current->uid == 0) { cap_set_full(bprm->cap_inheritable); cap_set_full(bprm->cap_permitted); } if (bprm->e_uid == 0) cap_set_full(bprm->cap_effective);//这里设置的 } memset(bprm->buf,0,BINPRM_BUF_SIZE); return kernel_read(bprm->file,0,bprm->buf,BINPRM_BUF_SIZE); }
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原文地址:http://blog.csdn.net/jltxgcy/article/details/44831699