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使用python实现的树遍历,包括宽度优先和深度优先
ef dfs(): tree = { ‘A‘: [‘B‘, ‘C‘], ‘B‘: [‘D‘, ‘E‘], ‘C‘: [‘F‘, ‘G‘], ‘D‘: [‘H‘, ‘I‘], ‘E‘: [], ‘F‘: [], ‘G‘: [], ‘H‘: [], ‘I‘: [] } leaf = [] to_crawl = deque([‘A‘]) while to_crawl: current = to_crawl.popleft() print current, to_crawl children = tree[current] if len(children)> 0: # width first # to_crawl.extend(children) # depth first to_crawl.extendleft(children[::-1]) print to_crawl else: leaf.append(current) print leaf
对于图的遍历稍微调整一下即可,主要是图需要考虑的重复遍历的问题,所以需要记录已经遍历过哪些节点,每次获得新的children之后减去已遍历过的节点即可
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原文地址:http://www.cnblogs.com/Jerryshome/p/4391598.html