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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1145 Accepted Submission(s): 476
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<cstdlib>
#include<algorithm>
#include<queue>
#include<stack>
#include<vector>
#include<set>
using namespace std;
int n,m,in[1010],dp[1010];
vector<int> e[1010],w[1010];
int main()
{
int a,b,c;
while(scanf("%d%d",&n,&m)!=EOF)
{
int ans=0;
for(int i=0;i<n;i++)
e[i].clear(),in[i]=0,dp[i]=0,w[i].clear();
for(int i=0;i<m;i++)
{
scanf("%d%d%d",&a,&b,&c);
e[a].push_back(b);
w[a].push_back(c);
in[b]++;
}
queue<int> q;
for(int i=0;i<n;i++)
{
if(in[i]==0)
q.push(i),dp[i]=1;
else
dp[i]=0;
}
while(!q.empty())
{
int x=q.front();
q.pop();
for(int i=0;i<e[x].size();i++)
{
int v=e[x][i];
dp[v]=max(dp[v],dp[x]+w[x][i]);
if(--in[v]==0)
{
q.push(v);
}
}
}
for(int i=0;i<n;i++)
{
if(ans<dp[i])
ans=dp[i];
}
printf("%d\n",ans);
}
return 0;
}
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原文地址:http://www.cnblogs.com/a972290869/p/4401899.html