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Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1145    Accepted Submission(s): 476
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<cstdlib>
#include<algorithm>
#include<queue>
#include<stack>
#include<vector>
#include<set>
using namespace std;
int n,m,in[1010],dp[1010];
vector<int> e[1010],w[1010];
int main()
{
    int a,b,c;
    while(scanf("%d%d",&n,&m)!=EOF)
    {
        int ans=0;
        for(int i=0;i<n;i++)
            e[i].clear(),in[i]=0,dp[i]=0,w[i].clear();
        for(int i=0;i<m;i++)
        {
            scanf("%d%d%d",&a,&b,&c);
            e[a].push_back(b);
            w[a].push_back(c);
            in[b]++;
        }
        queue<int> q;
        for(int i=0;i<n;i++)
        {
            if(in[i]==0)
                q.push(i),dp[i]=1;
            else
                dp[i]=0;
        }
        while(!q.empty())
        {
            int x=q.front();
            q.pop();
            for(int i=0;i<e[x].size();i++)
            {
                int v=e[x][i];
                dp[v]=max(dp[v],dp[x]+w[x][i]);
                if(--in[v]==0)
                {
                    q.push(v);
                }
            }
        }
        for(int i=0;i<n;i++)
        {
            if(ans<dp[i])
                ans=dp[i];
        }
        printf("%d\n",ans);
    }
    return 0;
}
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原文地址:http://www.cnblogs.com/a972290869/p/4401899.html