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又是一道WA成狗的题,最后发现原来是结果溢出了。。
代码:
1 #include <iostream> 2 #include <cstring> 3 4 using namespace std; 5 6 #define MAX_N 100008 7 8 int N; 9 long long a[MAX_N]; 10 long long b[MAX_N]; 11 12 long long count(int l, int r) { 13 if (l >= r) 14 return 0; 15 16 long long res = 0; 17 int m = (l + r) / 2; 18 res += count(l, m); 19 res += count(m + 1, r); 20 int i = l; 21 int j = m + 1; 22 int k = 0; 23 while (i <= m && j <= r) { 24 if (a[i] <= a[j]) { 25 b[k++] = a[i++]; 26 } 27 else { 28 res += (m - i + 1); 29 b[k++] = a[j++]; 30 } 31 } 32 while (i <= m) 33 b[k++] = a[i++]; 34 while (j <= r) 35 b[k++] = a[j++]; 36 37 while (k--) 38 a[l + k] = b[k]; 39 return res; 40 } 41 42 int main() { 43 scanf("%d", &N); 44 for (int i = 0; i < N; i++) 45 scanf("%lld", &(a[i])); 46 printf("%lld\n", count(0, N - 1)); 47 return 0; 48 }
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原文地址:http://www.cnblogs.com/boring09/p/4415917.html