标签:java获取时间反转
public static void main(String[] args) throws Exception { SimpleDateFormat sdf=new SimpleDateFormat("yyyyMMdd"); String str = (sdf.format(new Date())); char[] dist = new char[str.length()]; for(int x = str.length() - 1, p = 0; x >= 0; x--){ dist[p++] = str.charAt(x); } BigInteger aa =new BigInteger("99999999"); BigInteger bb= new BigInteger(new String(dist)); BigInteger sub=aa.subtract(bb); System.out.println(sub.toString()); //System.out.println(new String(dist)); }
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标签:java获取时间反转
原文地址:http://liang3391.blog.51cto.com/178205/1632911