杭电1379（DNA Sorting）java面向对象编程

One measure of ``unsortedness‘‘ in a sequence is the number of pairs of entries that are out of order with respect to each other. For instance, in the letter sequence ``DAABEC‘‘, this measure is 5, since D is greater than four letters to its right and E is greater than one letter to its right. This measure is called the number of inversions in the sequence. The sequence ``AACEDGG‘‘ has only one inversion (E and D)--it is nearly sorted--while the sequence ``ZWQM‘‘ has 6 inversions (it is as unsorted as can be--exactly the reverse of sorted).

You are responsible for cataloguing a sequence of DNA strings (sequences containing only the four letters A, C, G, and T). However, you want to catalog them, not in alphabetical order, but rather in order of ``sortedness‘‘, from ``most sorted‘‘ to ``least sorted‘‘. All the strings are of the same length.


This problem contains multiple test cases!

The first line of a multiple input is an integer N, then a blank line followed by N input blocks. Each input block is in the format indicated in the problem description. There is a blank line between input blocks.

The output format consists of N output blocks. There is a blank line between output blocks.

The first line contains two integers: a positive integer n (0 < n <= 50) giving the length of the strings; and a positive integer m (1 < m <= 100) giving the number of strings. These are followed by m lines, each containing a string of length n.

Output the list of input strings, arranged from ``most sorted‘‘ to ``least sorted‘‘. If two or more strings are equally sorted, list them in the same order they are in the input file.

1

10 6
AACATGAAGG
TTTTGGCCAA
TTTGGCCAAA
GATCAGATTT
CCCGGGGGGA
ATCGATGCAT

CCCGGGGGGA
AACATGAAGG
GATCAGATTT
ATCGATGCAT
TTTTGGCCAA
TTTGGCCAAA

import java.util.*;
class Main{
	public static void main(String[] args){
		int n,m,i,j,t;
		String str;
		Scanner sc=new Scanner(System.in);
		t=sc.nextInt();
		while(t-->0){
			n=sc.nextInt();
			m=sc.nextInt();
			sc.nextLine();
			StringSort[] strs=new StringSort[m];
			for(i=0;i<m;i++){
				str=sc.nextLine();
				strs[i]=new StringSort(str);
			}
			for(i=0;i<m;i++){
				strs[i].measure();
			}
			sort(strs);
			for(i=0;i<m;i++){
				System.out.println(strs[i].str);
			}
		}
	}
	public static void sort(StringSort[] strs){	
		for(int i=0;i<strs.length-1;i++){
				int minIndex=i;
				for(int j=i+1;j<strs.length;j++){
					if(strs[j].count<strs[minIndex].count){
						minIndex=j;
					}
				}
				if(minIndex!=i){
					StringSort temp=strs[i];
					strs[i]=strs[minIndex];
					strs[minIndex]=temp;
				}
		}
	}
}
class StringSort{
	String str;
	int count;
	public StringSort(String str){
		this.str=str;
		this.count=0;
	}
	public void measure(){
		for(int i=0;i<str.length()-1;i++){
			for(int j=i+1;j<str.length();j++){
				if(str.charAt(i)>str.charAt(j)){
					count++;
				}
			}
		}
	}
}