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实现了EXCEL中的IRR函数。
public static double irr(double[] income) { return irr(income, 0.1D); } public static double irr(double[] values, double guess) { int maxIterationCount = 20; double absoluteAccuracy = 1.0E-007D; double x0 = guess; int i = 0; while (i < maxIterationCount) { double fValue = 0.0D; double fDerivative = 0.0D; for (int k = 0; k < values.length; k++) { fValue += values[k] / Math.pow(1.0D + x0, k); fDerivative += -k * values[k] / Math.pow(1.0D + x0, k + 1); } double x1 = x0 - fValue / fDerivative; if (Math.abs(x1 - x0) <= absoluteAccuracy) { return x1; } x0 = x1; i++; } return (0.0D / 0.0D); } public static void main(String[] args) { double[] income = {-9272.49,0,0,0,0,0,0,0,0,0,888.49,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,888.49,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,888.49,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,888.49,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,888.49,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,888.49,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,888.49,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,888.49,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,888.49,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,888.49,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,888.49,}; double ret = irr(income,0.00001d) ; System.out.println(new BigDecimal(ret)); }
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原文地址:http://my.oschina.net/kanlianhui/blog/403865