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Google多线程面试题: 4个线程向4个文件里写入数据, 每个线程只能写一个值

时间:2015-04-21 18:05:08      阅读:173      评论:0      收藏:0      [点我收藏+]

标签:多线程   面试题   算法   互斥      

By Long Luo

个人博客链接

最近在学习Java多线程时,遇到了一个下面的笔试题,题目如下:

编写一个程序,程序会启动4个线程,向4个文件A,B,C,D里写入数据,每个线程只能写一个值。 
    线程A:只写A
    线程B:只写B 
    线程C:只写C 
    线程D:只写D 

4个文件A,B,C,D。 

程序运行起来,4个文件的写入结果如下: 
    A:ABCDABCD... 
    B:BCDABCDA... 
    C:CDABCDAB... 
    D:DABCDABC... 

网上搜索了下,好像还是一个Google笔试题,这个问题涉及到的知识点有:多线程, 并发, , 线程间通信

个人分析过程:
1. 创建4个线程;
2. 每个线程在输出时都需要加锁;
3. 操作文件的代码要加锁;
4. 一个线程完成之后,通知下一个要执行的线程;

根据以上分析,可以写出如下代码:

package com.imlongluo.Practise;

import java.io.BufferedWriter;
import java.io.File;
import java.io.FileOutputStream;
import java.io.OutputStreamWriter;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;

public class Practise {

    public static void main(String[] args) {

        final Task task = new Task();

        /** 创建4个线程,同时启动 */
        /**
         * Thread A
         */
        new Thread(new Runnable() {

            @Override
            public void run() {
                for (int i = 0; i < 10; i++) {
                    task.outputA();
                }
            }
        }, " Thread A").start();

        /**
         * Thread B
         */
        new Thread(new Runnable() {

            @Override
            public void run() {
                for (int i = 0; i < 10; i++) {
                    task.outputB();
                }
            }
        }, "Thread B").start();

        /**
         * Thread C
         */
        new Thread(new Runnable() {

            @Override
            public void run() {
                for (int i = 0; i < 10; i++) {
                    task.outputC();
                }
            }
        }, "Thread C").start();

        /**
         * Thread D
         */
        new Thread(new Runnable() {

            @Override
            public void run() {
                for (int i = 0; i < 10; i++) {
                    task.outputD();
                }
            }
        }, "Thread D").start();
    }

    /**
    任务类
    */
    public static class Task {
        /**
        创建一个Lock锁对象
        */
        private Lock lock = new ReentrantLock();

        private BufferedWriter bw1 = null;
        private BufferedWriter bw2 = null;
        private BufferedWriter bw3 = null;
        private BufferedWriter bw4 = null;

        private int ctl = 0;

        /**
         * Condition: 线程条件  
         */
        private Condition cond1 = lock.newCondition();
        private Condition cond2 = lock.newCondition();
        private Condition cond3 = lock.newCondition();
        private Condition cond4 = lock.newCondition();

        private boolean[] outputThisRound = { false, true, true, true };

        public Task() {
            try {
                bw1 = new BufferedWriter(new OutputStreamWriter(new FileOutputStream(new File(
                        "/Users/luolong/Code/Android/workspace/MultiThreads/A.txt"))));
                bw2 = new BufferedWriter(new OutputStreamWriter(new FileOutputStream(new File(
                        "/Users/luolong/Code/Android/workspace/MultiThreads/B.txt"))));
                bw3 = new BufferedWriter(new OutputStreamWriter(new FileOutputStream(new File(
                        "/Users/luolong/Code/Android/workspace/MultiThreads/C.txt"))));
                bw4 = new BufferedWriter(new OutputStreamWriter(new FileOutputStream(new File(
                        "/Users/luolong/Code/Android/workspace/MultiThreads/D.txt"))));
            } catch (Exception e) {
                e.printStackTrace();
            }
        }

        public void outputA() {

            lock.lock();

            try {
                while (outputThisRound[0]) {
                    System.out.println("outputA begin to await!");
                    cond1.await(); //阻塞A线程 
                }

                if (ctl % 4 == 0) {
                    bw1.write("A");
                    bw1.flush();
                } else if (ctl % 4 == 1) {
                    bw4.write("A");
                    bw4.flush();
                } else if (ctl % 4 == 2) {
                    bw3.write("A");
                    bw3.flush();
                } else if (ctl % 4 == 3) {
                    bw2.write("A");
                    bw2.flush();
                }

                outputThisRound[0] = true;
                outputThisRound[1] = false;

                System.out.println("outputA signal outputB!");
                cond2.signal(); //唤醒B线程
            } catch (Exception e) {
                e.printStackTrace();
            } finally {
                lock.unlock();
            }

        }

        public void outputB() {

            lock.lock();

            try {
                while (outputThisRound[1]) {
                    System.out.println("outputB begin to await!");
                    cond2.await();
                }

                if (ctl % 4 == 0) {
                    bw2.write("B");
                    bw2.flush();
                } else if (ctl % 4 == 1) {
                    bw1.write("B");
                    bw1.flush();
                } else if (ctl % 4 == 2) {
                    bw4.write("B");
                    bw4.flush();
                } else if (ctl % 4 == 3) {
                    bw3.write("B");
                    bw3.flush();
                }

                outputThisRound[1] = true;
                outputThisRound[2] = false;
                System.out.println("outputB signal outputC!");
                cond3.signal();
            } catch (Exception e) {
                e.printStackTrace();
            } finally {
                lock.unlock();
            }
        }

        public void outputC() {
            lock.lock();
            try {
                while (outputThisRound[2]) {
                    System.out.println("outputC begin to await!");
                    cond3.await();
                }

                if (ctl % 4 == 0) {
                    bw3.write("C");
                    bw3.flush();
                } else if (ctl % 4 == 1) {
                    bw2.write("C");
                    bw2.flush();
                } else if (ctl % 4 == 2) {
                    bw1.write("C");
                    bw1.flush();
                } else if (ctl % 4 == 3) {
                    bw4.write("C");
                    bw4.flush();
                }

                outputThisRound[2] = true;
                outputThisRound[3] = false;
                System.out.println("outputC signal outputD!");
                cond4.signal();
            } catch (Exception e) {
                e.printStackTrace();
            } finally {
                lock.unlock();
            }
        }

        public void outputD() {
            lock.lock();

            try {
                while (outputThisRound[3]) {
                    System.out.println("outputD begin to await!");
                    cond4.await();
                }

                if (ctl % 4 == 0) {
                    bw4.write("D");
                    bw4.flush();
                } else if (ctl % 4 == 1) {
                    bw3.write("D");
                    bw3.flush();
                } else if (ctl % 4 == 2) {
                    bw2.write("D");
                    bw2.flush();
                } else if (ctl % 4 == 3) {
                    bw1.write("D");
                    bw1.flush();
                }

                outputThisRound[3] = true;
                outputThisRound[0] = false;
                ctl++;
                System.out.println("outputD signal outputA!");
                cond1.signal();
            } catch (Exception e) {
                e.printStackTrace();
            } finally {
                lock.unlock();
            }
        }
    }
}

以上。

如果大家还有其他更好的方法,欢迎一起讨论:-)

Created by Long Luo at 2015-04-09 22:14:02 @Shenzhen, China.
Completed By Long Luo at 2015-04-09 23:46:29 @Shenzhen, China.

Google多线程面试题: 4个线程向4个文件里写入数据, 每个线程只能写一个值

标签:多线程   面试题   算法   互斥      

原文地址:http://blog.csdn.net/tcpipstack/article/details/45173633

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