使用jquery再次封装ajax

 $.fn.ajaxSend = function (type, url, postdata, onSuccess) {
        $.ajax({
            async: false,
            url: url,
            type: type,
            data: postdata == null|| postdata == "" ? "" : postdata,
            datatype: "json",
            cache: false,
            contentType: "application/json; charset=utf-8",
            complete: $.OnAjaxComplete,
            success: function (data) {
                onSuccess(data);
            },
            error: $.OnAjaxError
        });
    };

function postTest() {
        $(this).ajaxSend("post", "/ajaxTest1.ashx", "", function (res) {
            alert(res);
        });
    }