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LeetCode (24) Happy Number

时间:2015-04-26 12:27:42      阅读:114      评论:0      收藏:0      [点我收藏+]

标签:leetcode   算法   c++   

题目描述

Write an algorithm to determine if a number is “happy”.

A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

Example: 19 is a happy number

  • 12+92=82
  • 82+22=68
  • 62+82=100

本题比较简单,题目要求对任意一个正整数,不断各个数位上数字的平方和,若最终收敛为1,则该数字为happy number,否则程序可能从某个数开始陷入循环。这道题目我们只用根据规则进行计算,并使用一个哈希表存储已经出现过的数字即可。

class Solution {
public:
    bool isHappy(int n) {
        if (n < 1)
            return false;
        if (n == 1)
            return true;
        unordered_set<int> showedNums;
        showedNums.insert(n);

        while(true)
        {
            int s = 0;
            while(n)
            {
                s += (n % 10) * (n % 10);
                n = n / 10;
            }

            if (s == 1)
                return true;
            else if (showedNums.find(s) != showedNums.end())
                return false;
            n = s;
            showedNums.insert(s);
        }
    }
};

LeetCode (24) Happy Number

标签:leetcode   算法   c++   

原文地址:http://blog.csdn.net/angelazy/article/details/45286625

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